使用字典替换字符串列表中的值

Question

我正在尝试使用字典快速替换列表中每个字符串中的不正确单词。

注意：我正在尝试创建一个自定义函数，我可以创建的唯一解决方案是一组嵌套的“for 循环”，这在计算上是禁止的 考虑到我需要处理的实际数据长度超过 150,000。

考虑一下：

test_combine = ["cat", "dog", "Hello", "Johnny", "You",
 "123_happy_goose", "123_happy", "45_goose", "45_lamegoose"]

现在实际上，这些是地址，但我创建了这个示例问题。我想用字典替换这些：

replace_dic = {"cat":"dog", "_happy_":"_sad_", "_goose\\b":"duck", "Johnny":"john"}

我的文件目前只使用下划线，我在匹配时使用它们以确保仅替换某些情况。示例：如果我只想更改 happy 如果它是一个中间词，我会 re.sub 和 "_happy_" 这样只有 "123_happy_goose" 被更改，而不是 "123_happy."

理想情况下，正确的函数会返回

["dog", "dog", "Addition", "Hello", "john", "You",
 "123_sad_goose", "123_happy", "45_duck", "45_lamegoose"]

Answer 1

def replace(lst,dct):
    ar = []
    for i in lst:
        for k in dct.keys():
            i=i.replace(k,dct[k])
        ar.append(i)
    return ar

test_combine = ["cat", "dog", "Hello", "Johnny", "You",
 "123_happy_goose", "123_happy", "45_goose", "45_lamegoose"]

replace_dic = {"cat":"dog", "_happy_":"_sad_", "_goose\\b":"duck", "Johnny":"john"}

print(replace(test_combine,replace_dic))