SQL 获取子字符串列表，然后用作 LIKE 的值

Question

我想使用子字符串列表作为LIKE 子句的值。

考虑下表：

菌株

id    name
-------------------------------------------------------
562   B6;129 (Bnip3 KO)
563   B6;129 (BNIP3 Wt) [pregnant]
564   B6;129 (BNIP3 Wt) [older than 21 days]
720   BALB/C T(x:11)38H (T38H)
721   BALB/C [older than 21 days]

链接 (l)

id    protocol_id     strain_id
-------------------------------------------------------
1     61846           563
2     13487           564
3     79465           721
4     41699           720

动物（一）

id    group_id        strain_id
-------------------------------------------------------
24    9666            563
25    9666            720

通常我会提供一个我尝试过的查询，但这次我什么都没有。相反，让我分解一下我需要做的步骤：

1. 从同一group_id 下的所有动物的菌株名称中获取子字符串列表。
   • 为了得到子字符串，我想要(和)里面的字符串
   • 类似SELECT /* get the list of substrings */ FROM animals a LEFT JOIN strains s ON s.id = a.strain_id WHERE a.group_id = 9666
   • 在本例中，我需要以下列表：(BNIP3 Wt) 和 (T38H)
   • 如果(和)中包含多个值，则使用最后一个
2. 使用上述LIKE 子句的结果列表来获取protocol_id 的列表，其菌株名称包含子字符串。

我对解决方案的想法

SELECT l.protocol_id
FROM links l
LEFT JOIN strains s
ON s.id = l.strain_id
WHERE s.name LIKE (/* put the list here with the % for wildcards */)

我想要得到的最终结果如下：

protocol_id
------------------------------
61846
13487
41699

Answer 1

SQL Fiddle

Oracle 11g R2 架构设置：

CREATE TABLE Strains (id, name ) AS
SELECT 562,   'B6;129 (Bnip3 KO)' FROM DUAL UNION ALL
SELECT 563,   'B6;129 (BNIP3 Wt) [pregnant]' FROM DUAL UNION ALL
SELECT 564,   'B6;129 (BNIP3 Wt) [older than 21 days]' FROM DUAL UNION ALL
SELECT 720,   'BALB/C T(x:11)38H (T38H)' FROM DUAL UNION ALL
SELECT 721,   'BALB/C [older than 21 days]' FROM DUAL;

CREATE TABLE Links (id, protocol_id, strain_id ) AS
SELECT 1,     61846,           563 FROM DUAL UNION ALL
SELECT 2,     13487,           564 FROM DUAL UNION ALL
SELECT 3,     79465,           721 FROM DUAL UNION ALL
SELECT 4,     41699,           720 FROM DUAL;

CREATE TABLE Animals (id, group_id, strain_id ) AS
SELECT 24,    9666,            563 FROM DUAL UNION ALL
SELECT 25,    9666,            720 FROM DUAL;

查询 1：

SELECT l.protocol_id
FROM   links l
       INNER JOIN strains s
       ON s.id = l.strain_id
       INNER JOIN (
         SELECT REGEXP_SUBSTR( s.name, '\(.*?\)', 1, l.COLUMN_VALUE ) AS id
         FROM   strains s,
                TABLE( 
                  CAST(
                    MULTISET(
                      SELECT LEVEL
                      FROM   DUAL
                      CONNECT BY LEVEL <= REGEXP_COUNT( s.name, '\(.*?\)' )
                    ) AS SYS.ODCINUMBERLIST
                  )
                ) l,
                animals a
         WHERE  a.strain_id = s.id
         AND    a.group_id = 9666
       ) t
       ON s.name LIKE '%' || t.id || '%'

Results：

| PROTOCOL_ID |
|-------------|
|       61846 |
|       13487 |
|       41699 |
|       41699 |

Answer 2

您也许可以使用 REGEXP_LIKE 解决问题

例如

With strains (id, name) as
(
          select 562,   'B6;129 (Bnip3 KO)' from dual
union all select 563,   'B6;129 (BNIP3 Wt) [pregnant]'  from dual
union all select 564,   'B6;129 (BNIP3 Wt) [older than 21 days]'  from dual
union all select 720,   'BALB/C T(x:11)38H (T38H)'  from dual
union all select 721,   'BALB/C [older than 21 days]'  from dual
)
    ,Links (id, protocol_id, strain_id ) as
(    
          select 1,     61846,           563 from dual
union all select 2,     13487,           564 from dual
union all select 3,     79465,           721 from dual
union all select 4,     41699,           720 from dual
)
   ,Animals (id, group_id, strain_id) as
(   
          select 24,    9666,            563 from dual
union all select 25,    9666,            720 from dual
)
SELECT l.protocol_id
FROM links l
LEFT JOIN strains s ON s.id = l.strain_id
WHERE  REGEXP_LIKE (s.name, '*BNIP3|T38H*');