在给定的字符串集中查找字符串 bt 逗号分隔

Question

我需要从下面的字符串中获取第三个子字符串是示例，使用 SQL Server 2008。

string1:-

('C20080703115333MCTTtettett','24','6101349328','Bundled Standard','4','2.00','Testing Insert for New SP',','PD2013021002584832540')

想要的结果：- 6101349328

string2:-

('C20080703115333MCTTetew','24','7101349328','Bundled Standard','4','2.00','Testing Insert for New SP',','PD2013021002584832540')

想要的结果：- 7101349328

string3:-

('C20080703115333MCTTteetew','24tt','8101349328','Bundled Standard','4','2.00','Testing Insert for New SP',','PD2013021002584832540')

想要的结果：- 8101349328

string4:-

('C20080703','24','111101349328','Bundled Standard','4','2.00','Testing Insert for New SP',','PD2013021002584832540')

想要的结果：- 111101349328

提前致谢。

Answer 1

试试这样的：

select val = substring
  (
    str
    , charindex(',', str, charindex(',',str, 0) + 1) + 2
    , charindex(',', str, charindex(',', str, charindex(',',str, 0) + 1) + 1)
       - (charindex(',', str, charindex(',',str, 0) + 1) + 3)
  )
from strings

这给出了：

6101349328
7101349328
8101349328
111101349328

SQL Fiddle example.