【发布时间】:2019-07-16 11:42:09
【问题描述】:
控制器给我结果,TempData["DCFormList"] 显示计数3(键、值和成功消息),但在 AJAX 调用中我得到alert("fail")。
public ActionResult INTImportData()
{
if (Session["UserLogon"] != null)
{
BLINTForms objForm = new BLINTForms();
objDCFormList = new DCFormList();
int jobId = Session["Job_ID"] == null ? 0 : (int)Session["Job_ID"];
ViewBag.jobId = jobId;
objDCFormList.Form = objForm.GetINTFormTempDataByJobId(jobId);
TempData["DCFormList"] = objDCFormList.Form;
return View(objDCFormList.Form);
}
else
return Redirect("~/Account/Login");
}
function GetINTFormTempData(JobId) {
var result = null;
$.ajax({
type: "GET",
url: '/ImportForms/GetINTFormTempDataByJobId',
data: { jobId: JobId },
traditional: false,
success: function (data)
{
result = data;
alert ("JobId");
LoadINTData(result);
if (result.length > 0)
$(".upload").show();
else
$(".upload").hide();
},
error: function (data)
{
alert("fail");
Success = false;
}
});
public List<DCForm> GetINTFormTempDataByJobId(int jobId)
{
objDatabaseHelper = new DatabaseHelper();
List<DCForm> objDCFormList = new List<DCForm>();
DCForm objDCForm;
int record = 0;
try
{
objDatabaseHelper.AddParameter("Job_ID", jobId == 0 ? DBNull.Value : (object)jobId);
DbDataReader reader = objDatabaseHelper.ExecuteReader(BLDBRoutines.SP_GETINTFORMTEMPDATA, CommandType.StoredProcedure);
if (reader.HasRows)
{
while (reader.Read())
{
objDCForm = new DCForm();
objDCForm.SerialNo = ++record;
objDCForm.PayerId = reader.IsDBNull(reader.GetOrdinal("PayerId")) ? 0 : reader.GetInt32(reader.GetOrdinal("PayerId"));
objDCFormList.Add(objDCForm);
}
}
return objDCFormList;
}
catch (Exception exce)
{
throw exce;
}
finally
{
if (objDatabaseHelper != null)
objDatabaseHelper.Dispose();
}
}
public class DCForm : DataOperationResponse
{
public int SerialNo { get; set; }
public int PayerId { get; set; }
public class DCFormList : DataOperationResponse
{
private List<DCForm> _form = null;
public DCFormList()
{
if (_form == null)
_form = new List<DCForm>();
}
public List<DCForm> Form
{
get { return _form; }
set { _form = value; }
}
}
【问题讨论】:
-
首先,请将您的实际代码添加到问题中,而不是图像。其次,如果
error处理程序被击中,那么您的服务器端代码将失败并且实际上没有返回任何数据。我建议在其中放置一个断点并逐步调试。第三,删除async: false。这是非常糟糕的做法。
标签: c# jquery asp.net-mvc-5 asp.net-ajax