【问题标题】:My calculator won't work c# console application我的计算器无法使用 c# 控制台应用程序
【发布时间】:2015-09-20 13:02:25
【问题描述】:

这可能是一个非常简单的解决方案,但是当它给出 3 条错误消息时:

The name 'iNum1' does not exist in the current context  
The name 'iNum2' does not exist in the current context  
The name 'soOper' does not exist in the current context 

当我删除我的最后一行代码时,它可以工作,但没有它我无法计算它。我希望有人能帮帮忙。这是代码。

//information
    Console.WriteLine("This is a calculator");

    //Let them fill in the first number
    Console.WriteLine("Please enter the first number");
    bool bNoNum1 = true;
    while (bNoNum1)
    {

        string sNum1 = Console.ReadLine();

        try
        {
            int iNum1 = int.Parse(sNum1);
            bNoNum1 = false;
        }

        catch (Exception)
        {
            Console.WriteLine("That's not a number");
        }

    }



    //Let them fill in (*, +, / of -)
    Console.WriteLine("Please enter +, +, - or :");

    bool bNoOperator = true;


    do
    {
        string sOper = Console.ReadLine();

        if (sOper == "x")
        {
            string soOper = "*";
            bNoOperator = false;
        }
        else if (sOper == ":")
        {
            string soOper = "/";
            bNoOperator = false;
        }
        else if (sOper == "+")
        {
            string soOper = "+";
            bNoOperator = false;
        }
        else if (sOper == "-")
        {
            string soOper = "-";
            bNoOperator = false;
        }
        else
        {
            Console.WriteLine("De operator " + sOper + " Is niet bekend. Kies uit +, -, x of :");
        }
    } while (bNoOperator);


    //Enter second number
    Console.WriteLine("Please enter the second number");

    bool bNoNum2 = true;
    while (bNoNum2)
    {
        string sNum2 = Console.ReadLine();

        try
        {
            int iNum2 = int.Parse(sNum2);
            bNoNum2 = false;
        }

        catch (Exception)
        {
            Console.WriteLine("That's not a number");
        }
    }

    //calculating

    int uitkomst = iNum1 + soOper + iNum2;

【问题讨论】:

标签: c# scope calculator


【解决方案1】:

您需要在上下文之外将这 3 个变量声明为全局变量,将这些变量放在 " 行上方,像这样,

Console.WriteLine("This is a calculator");
"
int iNum1;
int iNum2;
string sOper = "";

【讨论】:

    【解决方案2】:

    您在错误的位置声明 iNum1 和 iNum2 - 在一些内括号内。它们在最后一行所在的范围内是未知的。在不同的级别声明这些变量。

    无论如何,当你这样做时,你会遇到另一个问题:soOper 是一个字符串。您正在添加一个带有字符串和另一个 int 的 int。

    【讨论】:

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