【发布时间】:2014-02-20 20:56:33
【问题描述】:
我正在尝试编写一个 C++ 代码,其中用户输入日期并使用 John Conway 的世界末日算法输出日期所在的星期几。
我正在尝试访问在函数 dayofthemonth 中声明和定义的变量 z,并在名为 dayoftheweek 的函数中使用它。请记住,我对 C++ 很陌生,所以如果你能尽可能简单地回答,那将有很大帮助。代码如下:
#include <iostream>
#include <string>
using namespace std;
int dayofthemonth (int year, int month){
int z;
if ((year % 400 == 0 || year % 100 !=0) && (year % 4 == 0)){ //reference day of the month for leap years
cout << year << " is a leap year." << endl;
if (month == 1){
cout << "The doomsday for month " << month << " is 4." << endl;
z = 4;
}
if (month == 2){
cout << "The doomsday for month " << month << " is 1." << endl;
z = 1;
}
if (month == 3){
cout << "The doomsday for month " << month << " is 0." << endl;
z = 0;
}
if (month == 4){
cout << "The doomsday for month " << month << " is 4." << endl;
z = 4;
}
if (month == 5){
cout << "The doomsday for month " << month << " is 9." << endl;
z = 9;
}
if (month == 6){
cout << "The doomsday for month " << month << " is 6." << endl;
z = 6;
}
if (month == 7){
cout << "The doomsday for month " << month << " is 11." << endl;
z = 11;
}
if (month == 8){
cout << "The doomsday for month " << month << " is 8." << endl;
z = 8;
}
if (month == 9){
cout << "The doomsday for month " << month << " is 5." << endl;
z = 5;
}
if (month == 10){
cout << "The doomsday for month " << month << " is 10." << endl;
z = 10;
}
if (month == 11){
cout << "The doomsday for month " << month << " is 7." << endl;
z = 7;
}
if (month == 12){
cout << "The doomsday for month " << month << " is 12." << endl;
z = 12;
}
}
else{ //reference day of the month for non-leap years
cout << year << " is not a leap year." << endl;
if (month == 1){
cout << "The doomsday for month " << month << " is 3." << endl;
z = 3;
}
if (month == 2){
cout << "The doomsday for month " << month << " is 0." << endl;
z = 0;
}
if (month == 3){
cout << "The doomsday for month " << month << " is 0." << endl;
z = 0;
}
if (month == 4){
cout << "The doomsday for month " << month << " is 4." << endl;
z = 4;
}
if (month == 5){
cout << "The doomsday for month " << month << " is 9." << endl;
z = 9;
}
if (month == 6){
cout << "The doomsday for month " << month << " is 6." << endl;
z = 6;
}
if (month == 7){
cout << "The doomsday for month " << month << " is 11." << endl;
z = 11;
}
if (month == 8){
cout << "The doomsday for month " << month << " is 8." << endl;
z = 8;
}
if (month == 9){
cout << "The doomsday for month " << month << " is 5." << endl;
z = 5;
}
if (month == 10){
cout << "The doomsday for month " << month << " is 10." << endl;
z = 10;
}
if (month == 11){
cout << "The doomsday for month " << month << " is 7." << endl;
z = 7;
}
if (month == 12){
cout << "The doomsday for month " << month << " is 12." << endl;
z = 12;
}
}
}
int doomsday (int year){ //reference day of the week
int a, b, c , d, e, x;
a = ((year/100) % 4);
b = (year % 100);
c = (b/12);
d = (b % 12);
e = (d/4);
x = ((c + d + e + (5*a) + 2) % 7);
if (x == 0){
cout << "The doomsday for " << year << " is Sunday." << endl;
}
else if (x == 1){
cout << "The doomsday for " << year << " is Monday." << endl;
}
else if (x == 2){
cout << "The doomsday for " << year << " is Tuesday." << endl;
}
else if (x == 3){
cout << "The doomsday for " << year << " is Wednesday." << endl;
}
else if (x == 4){
cout << "The doomsday for " << year << " is Thursday." << endl;
}
else if (x == 5){
cout << "The doomsday for " << year << " is Friday." << endl;
}
else if (x == 6){
cout << "The doomsday for " << year << " is Saturday." << endl;
}
}
void dayoftheweek(int month, int day, int year}(
int r;
cout << "You want to find out what day of the week " << month << "/" << day << "/" << year << " lies on." << endl;
doomsday(year);
r = (day - z) + 14; //offset between the given day and the result of dayofthemonth function.
cout << r << endl;
}
int main(){
int year, month, day;
cout << "Enter the year." << endl;
cin >> year;
cout << "Enter the month using numbers 1-12." << endl;
cin >> month;
cout << "Enter the day." << endl;
cin >> day;
dayoftheweek(month, day, year);
system ("PAUSE");
return 0;
}
【问题讨论】:
-
int z;超出范围......你不能。您必须更改实施:)
-
你为什么不直接
return z?