【发布时间】：2012-12-23 11:37:10
【问题描述】：
我在使用 Springs 安全配置时遇到问题。我在下面分享我的代码。
我的问题是我希望 /user* url 和 /admin* url 只有在用户登录到我的应用程序时才能访问，我的应用程序有主要的 ajax 调用，所以我希望没有用户可以访问 /user* URL登录。但是当我尝试在网络浏览器中输入 URL 时，我什至没有重定向到登录页面，而是进入了输入 URL 的页面。
那么谁能帮我解决这个问题。
spring-security.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<http auto-config="true">
<intercept-url pattern="/user**" access="ROLE_USER" />
<form-login login-page="/login" default-target-url="/user/home"
authentication-failure-url="/loginfailed" />
<logout invalidate-session="true" logout-success-url="/logout" />
</http>
<authentication-manager>
<authentication-provider>
<jdbc-user-service data-source-ref="dataSource"
users-by-username-query="select USERNAME, PASSWORD from USER where USERNAME = ?"
authorities-by-username-query="ROLE_USER"
/>
</authentication-provider>
</authentication-manager>
web.xml
<?xml version="1.0" encoding="utf-8" standalone="no"?><web-app
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>Admin</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Admin</servlet-name>
<url-pattern>/admin*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>User</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>User</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/User-servlet.xml,
/WEB-INF/Spring-Datasource.xml,
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>SystemServiceServlet</servlet-name>
<servlet-class>com.google.api.server.spi.SystemServiceServlet</servlet-class>
<init-param>
<param-name>services</param-name>
<param-value/>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>SystemServiceServlet</servlet-name>
<url-pattern>/_ah/spi/*</url-pattern>
</servlet-mapping>
</web-app>
ControllerServlet.java
@Controller
public class UserController {
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String getUserLoginPage(){
return "user/index";
}
@RequestMapping(value = "/loginfailed", method = RequestMethod.GET)
public String showErrorLoginPage(ModelMap modelMap){
modelMap.addAttribute("message", "Invalid Login Credentials");
return "user/index";
}
@RequestMapping(value = "/user/home", method = RequestMethod.GET)
public String getUserHomePage(ModelMap modelMap, Principal principal){
//String name = principal.getName();
//modelMap.addAttribute("name", name);
return "user/home";
}
@RequestMapping(value = "/logout", method = RequestMethod.GET)
public String showLogoutPage(ModelMap modelMap){
return "user/index";
}
}
数据库设计/代码：
create table USER(ID BIGINT NOT NULL AUTO_INCREMENT, USERNAME varchar(20) NOT NULL UNIQUE, PASSWORD varchar(20) NOT NULL, FIRSTNAME varchar(25) NOT NULL, LASTNAME varchar(25) NOT NULL, UPDATED_ON varchar(25) NOT NULL, PRIMARY KEY (ID));
登录表单代码：
<form class="form-horizontal" method="POST"
action="<c:url value='/j_spring_security_check' />" id="loginForm">
<div class="span4"></div>
<div class="span5" style="background-color: #FBFBFC; border: solid 1px #CCC;padding: 30px 5px 30px 5px;">
<div class="span1"></div>
<fieldset>
<legend>Login Here</legend>
<div class="control-group">
<label for="username">Username</label>
<input type="text" name="j_username" id="username"
placeholder="Username"
title="Please enter your username" data-placement="right" />
<div class="clear"></div>
<span id="errorSpan"></span>
</div>
<div class="control-group">
<label for="password">Password</label>
<input type="password" name="j_password" id="password"
placeholder="Password" title="Please enter your password"
data-placement="right" />
<div class="clear"></div>
<span id="errorSpan"></span>
</div>
<div class="control-group">
<label> </label>
<input type="submit" class="btn btn-primary" value="Sign In" />
</div>
<div class="span1"></div>
</fieldset>
</div>
<div class="span3"></div>
</form>
【问题讨论】：
标签： java spring spring-mvc spring-security