【发布时间】:2017-05-06 04:03:34
【问题描述】:
我尝试将turn = 0 放在play 函数中
我在 Stackoverflow 上阅读了几个类似的问题,并试图将 global turn 放在我的函数内部和外部。这些不会引发错误,但也不会导致转弯限制。为什么?有关如何解决此问题的任何想法?
我的直觉说,因为我已将变量 turn 设置为 global,所以我将继续引用 turn=0 的值,因为它是在函数之外设置的,但因为它会像你一样运行迭代数字轮流,我错了。
这是我的代码:
from random import randint
board = []
for x in range(5):
board.append(["O"] * 5)
def print_board(board):
for row in board:
print " ".join(row)
print "Incredibly Simple Battleship!"
print_board(board)
def random_row(board):
return randint(0, len(board) - 1)
def random_col(board):
return randint(0, len(board[0]) - 1)
ship_row = random_row(board)
ship_col = random_col(board)
print ship_row #erase after testing
print ship_col
global turn
def play(guess_row,guess_col):
global turn
if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
else:
if turn == 4:
print "Game Over"
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
print_board(board)
print "Guess again:"
print "Turn ",turn,":"
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
turn += 1
play(guess_row,guess_col)
turn=0
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
play(guess_row,guess_col)
这是我不使用全局时的原始错误:
Traceback (most recent call last):
File "python", line 51, in <module>
File "python", line 30, in play
UnboundLocalError: local variable 'turn' referenced before assignment
NB 我想接受不使用global 的建议,但还没有找到替代方案。
【问题讨论】: