【问题标题】:Iterated global variable not triggering == condition迭代全局变量未触发 == 条件
【发布时间】:2017-05-06 04:03:34
【问题描述】:

我尝试将turn = 0 放在play 函数中 我在 Stackoverflow 上阅读了几个类似的问题,并试图将 global turn 放在我的函数内部和外部。这些不会引发错误,但也不会导致转弯限制。为什么?有关如何解决此问题的任何想法?

我的直觉说,因为我已将变量 turn 设置为 global,所以我将继续引用 turn=0 的值,因为它是在函数之外设置的,但因为它会像你一样运行迭代数字轮流,我错了。

这是我的代码:

from random import randint

board = []

for x in range(5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

print "Incredibly Simple Battleship!"
print_board(board)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row #erase after testing
print ship_col

global turn

def play(guess_row,guess_col):
  global turn
  if guess_row == ship_row and guess_col == ship_col:
    print "Congratulations! You sunk my battleship!"
  else:
    if turn == 4:
        print "Game Over"
    if guess_row not in range(5) or guess_col not in range(5):
        print "Oops, that's not even in the ocean."
    elif(board[guess_row][guess_col] == "X"):
        print "You guessed that one already."
    else:
        print "You missed my battleship!"
        board[guess_row][guess_col] = "X"
        print_board(board)
        print "Guess again:"
    print "Turn ",turn,":"
    guess_row = int(raw_input("Guess Row:"))
    guess_col = int(raw_input("Guess Col:"))
    turn += 1
    play(guess_row,guess_col)  


turn=0
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))      
play(guess_row,guess_col)

这是我不使用全局时的原始错误:

Traceback (most recent call last):
 File "python", line 51, in <module>
 File "python", line 30, in play
UnboundLocalError: local variable 'turn' referenced before assignment

NB 我想接受不使用global 的建议,但还没有找到替代方案。

【问题讨论】:

    标签: python scope global


    【解决方案1】:

    这是一个通过递归 play() 函数上的额外变量来跟踪转弯的版本。请注意,我还为您添加了一个回报,以便游戏可以在 Game Over 时结束。 :)

    from random import randint
    
    board = []
    
    for x in range(5):
        board.append(["O"] * 5)
    
    def print_board(board):
        for row in board:
            print " ".join(row)
    
    print "Incredibly Simple Battleship!"
    print_board(board)
    
    def random_row(board):
        return randint(0, len(board) - 1)
    
    def random_col(board):
        return randint(0, len(board[0]) - 1)
    
    ship_row = random_row(board)
    ship_col = random_col(board)
    print ship_row #erase after testing
    print ship_col
    
    
    def play(guess_row,guess_col, turn):
      if guess_row == ship_row and guess_col == ship_col:
        print "Congratulations! You sunk my battleship!"
      else:
        if turn == 4:
            print "Game Over"
            return
        if guess_row not in range(5) or guess_col not in range(5):
            print "Oops, that's not even in the ocean."
        elif(board[guess_row][guess_col] == "X"):
            print "You guessed that one already."
        else:
            print "You missed my battleship!"
            board[guess_row][guess_col] = "X"
            print_board(board)
            print "Guess again:"
        print "Turn ",turn,":"
        guess_row = int(raw_input("Guess Row:"))
        guess_col = int(raw_input("Guess Col:"))
        play(guess_row,guess_col, turn + 1)
    
    
    guess_row = int(raw_input("Guess Row:"))
    guess_col = int(raw_input("Guess Col:"))
    play(guess_row,guess_col, 0)
    

    【讨论】:

    • 所以你可以通过函数调用传入一个变量,并通过在函数(重新)调用中传递+1来迭代它?太棒了!
    • 甜,没问题。您的方法也可以工作,但您定义了两次全局转弯。在你的代码中取出第一个“全局转弯”,你应该很高兴(记住在 Game Over 之后还要添加那个 return 语句)。
    • 对不起,我以为我有!我尝试在函数之前取出global turn,我仍然可以玩很多回合。当我将它移到函数之前时,它会产生与之前类似的错误。 :s
    猜你喜欢
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 2015-04-08
    • 1970-01-01
    • 2021-10-30
    • 1970-01-01
    相关资源
    最近更新 更多