【发布时间】:2018-01-01 15:07:21
【问题描述】:
我想在页面加载事件的某些特定条件下显示模式弹出窗口,但它现在正在工作。
这是我的modalPopup:
<script type="text/javascript">
function openModal(message, header, url) {
$('#myModal').modal('show');
$('#lblMasterMessage').html(header);
$('#lblMasterbodyMessage').html(message);
$('#myModal').on('hidden.bs.modal', function(e) {
if (url != '') {
window.location = url;
}
});
}
</script>
<asp:Content ID="Content2" ContentPlaceHolderID="BodyContentPlaceHolder" runat="Server">
<div class="modal fade" id="myModal" runat="server">
<div class="modal-dialog">
<div class="modal-content" style="width: 400px; margin: 0 auto;">
<div class="modal-header" runat="server">
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span></button>
<h4 class="modal-title">
<label id="lblMasterMessage"></label>
</h4>
</div>
<div class="modal-body">
<label id="lblMasterbodyMessage"></label>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-primary" data-dismiss="modal" runat="server">Close</button>
</div>
</div>
</div>
</div>
</asp:Content>
从后端调用模态弹出窗口:
protected void Page_Load(object sender, EventArgs e)
{
if (dt.Rows.Count > 0)
{
BindGrid();
}
else
{
string message = "Files are not Generated!";
string header = "Info";
ScriptManager.RegisterStartupScript(this, this.GetType(), "popup","openModal('" + message + "','" + header + "','MemberHomePage.aspx');", true);
//ScriptManager.RegisterStartupScript(this, this.GetType(), "popup", "alert('Business Operation Files are not Generated!'); window.location ='MemberHomePage.aspx';", true);
}
}
当条件满足时,我无法显示弹出窗口。任何帮助将不胜感激。
【问题讨论】:
-
我认为这应该可以工作,除非您想在部分回发时显示弹出窗口或弹出模型的 ID 已更改。检查您的模型 ID
-
那个JavaScript函数
openModal(message, header, url)触发了吗? -
是的,我正在通过 javascript 触发。
标签: javascript c# jquery asp.net twitter-bootstrap