为什么我的代码会忽略我的刽子手游戏的 if 语句？（Python）答案

【问题标题】：Why does my code ignore my if statement for my hangman game? (python)为什么我的代码会忽略我的刽子手游戏的 if 语句？（Python）
【发布时间】：2021-07-28 03:55:33
【问题描述】：

我刚刚对我在下面编写的代码有疑问。我只是想知道我用“if guess not in secret_word:”写的 if 语句。当我按照当前编写的方式运行它时，条件甚至不会运行或出现。但是，当我将它与上面写的 for 语句交换时，它运行得很好。我对编程有点陌生，我只是想知道是否有人可以帮助我解决这个问题。为什么这里的条件顺序很重要？

'''

import random
from words import words

secret_word = random.choice(words)
secret_letters = list(secret_word)
blanks = " _ " * len(secret_word)
already_guessed = []
lives = 10

print(blanks)


def valid_guess(): # function to make sure the letter guessed is valid (ie, not previously guessed)
    is_letter = True
    lives = 10

    while True:
        guess = (input("\nGuess a letter:"))

        if guess in already_guessed:
            print("You have already guessed this letter")
        elif len(guess) != 1:
            print("Please guess a single letter:")
            is_letter = False
        elif guess not in "abcdefghijklmnopqrstuvwxyz":
            print("Please guess a LETTER:")
            is_letter = False

        if is_letter:
            already_guessed.append(guess)

        for guess in secret_word:
            if guess in already_guessed:
                print(guess + " ", end = "")
            else:
                print(" - ", end = "")

        if guess not in secret_word:
            lives -= 1
            print(f"You lost a life! You only have {lives}/10 left!")


while True:
    valid_guess()

'''

【问题讨论】：

您从用户输入中获得的guess 已被for guess in secret_word 覆盖。也许你想要if guess in secret_word，而不是for。

标签： python syntax

【解决方案1】：

你可以试试这个：

if guess in secret_word:
       if guess in already_guessed:
            print(guess + " ", end = "")
       else:
            print(" - ", end = "")

 elif guess not in secret_word:
       lives -= 1
       print(f"You lost a life! You only have {lives}/10 left!")

【讨论】：