python中的bash：sed未终止的s命令[重复]

Question

以下命令在 bash 中运行良好。

/folk/vlm/commandline/./vlmTool find -l all | grep -e "^Target ID" -e "City" -e "Zone" | sed "s#.*City.*#&\n#g" > new.txt

但在 python 中，当我尝试执行相同的命令时，我得到：

['sed', 's#.*City.*#&\n#g']
**sed: -e expression #1, char 12: unterminated `s' command**

代码：

#!/usr/local/bin/python -tt

import subprocess
import shlex
cmd = '/folk/vlm/commandline/./vlmTool find -l all | grep -e "^Target ID" -e "City" -e "Zone" | sed "s#.*City.*#&\n#g" > new.txt'
cmd2= "/folk/vlm/commandline/./vlmTool find -l all"
args1 = shlex.split(cmd2)
cmd3 = 'grep -e "^Target ID" -e "City" -e "Zone"'
args2 = shlex.split(cmd3)
cmd4 =  'sed "s#.*City.*#&\n#g"'
args3 = shlex.split(cmd4)
print args3
p1 = subprocess.Popen(args1, stdout=subprocess.PIPE)
p2 = subprocess.Popen(args2, stdin=p1.stdout, stdout=subprocess.PIPE)
p3 = subprocess.Popen(args3, stdin=p2.stdout, stdout=subprocess.PIPE)
p1.stdout.close()
p2.stdout.close()
output = p3.communicate()[0]

Answer 1

\n 序列在 python 中被理解为换行符的转义序列；所以 sed 认为你已经完成了 s 命令并开始一个新的命令。要获取包含在字符串中的反斜杠，可以将其转义，如 ...\\n... 或使用原始字符串：r's#.*City.*#&\n#g'