【发布时间】:2018-06-24 21:38:19
【问题描述】:
当我向列表中添加新项目时,它会为该特定项目创建一个删除按钮。我想知道如何获得删除按钮以从列表中删除该项目而不删除所有其他项目并将其从本地存储中删除。我以前试过让它工作,但没有运气。
<div class = 'wrapper'>
<h2>Tapas Order</h2
<p></p>
<ul class="plates">
<li>Loading Tapas...</li>
</ul>
<ul>
<form class='add-items'>
<input type='text' name='item' placeholder='Item Name' required>
<input type='submit' value='+ Add Item'>
</form>
</ul>
</div>
<script>
const addItems = document.querySelector('.add-items');
const itemsList = document.querySelector('.plates');
const items = JSON.parse(localStorage.getItem('items')) || [];
function addItem (e){
e.preventDefault();
const text = this.querySelector('[name=item]').value;
const item = {
text,
done: false
};
items.push(item);
populateList(items, itemsList);
localStorage.setItem('items', JSON.stringify(items));
this.reset();
}
function populateList(plates = [], platesList){
platesList.innerHTML = plates.map((plate, i) => {
return`
<li>
<input type='checkbox' data-index=${i} id='item${i}' ${plate.done ? 'checked' : ''}/>
<label for='item${i}'>${plate.text} </label>
<button id='delete'>delete</delete>
</li>
`;
}).join('');
}
function toggleDone(e){
if(!e.target.matches('input')) return;
const el = e.target;
const index = el.dataset.index;
items[index].done = !items[index].done;
localStorage.setItem('items', JSON.stringify(items));
populateList(items, itemsList);
}
addItems.addEventListener('submit', addItem);
itemsList.addEventListener('click', toggleDone);
populateList(items, itemsList);
</script>
【问题讨论】:
-
只需使用
localStorage.removeItem(items[index])。
标签: javascript html local-storage