【发布时间】:2012-03-24 16:17:12
【问题描述】:
关注按钮右对齐,但我希望 x 出现在关注取消关注按钮的右侧而不是左侧。我为按钮使用浮动右侧,也为 X 浮动右侧,但按钮浮动到 X 的右侧。如何反转这些,同时保持当我单击 X 时整行消失的功能?
我希望 X 出现在按钮的右侧,但如果我这样做了,按下 X 后功能将不再隐藏整行:
<?php
$users = show_users_userspage();
$following = following($_SESSION['user_id']);
if (count($users)){
?>
<table cellspacing='0' cellpadding='1' width='320'>
<?php
foreach ($users as $key => $value){
echo "<tr valign='bottom'>\n";
"<td>"."<div class='alert alert-success'>".$key ."</td>\n";
echo "<td><img src='/social_learning/images/thebombthumb.gif'> ".$value;
if (in_array($key,$following)){
echo "<small><a style='margin:10px 20px 0px 5px;float:right;' class='btn btn-danger btn-mini' href='/social_learning/php/action.php? id=$key&do=unfollow'>unfollow</a></small><a class='close' style='margin:10px 0px 0px 5px;' data- dismiss='alert'>×</a></div>";
}else{
echo " <small><a style='margin:10px 20px 0px 5px;float:right;' class='btn btn-warning btn-mini' href='/social_learning/php/action.php? id=$key&do=follow'>follow</a></small><a class='close'style='margin:10px 0px 0px 5px;' data- dismiss='alert'>×</a></div>";
}
echo "</td>\n";
echo "</tr>\n";
}
?>
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标签: javascript php css button html-table