【发布时间】:2015-12-08 00:52:59
【问题描述】:
我想做的是为快捷键分配一个按钮,例如 $TurnOnButton 作为键“Q”,$TurnOffButton 作为我键盘上的键“W”。
所以基本上,在我下面的例子中。当脚本运行并且表单存在时,我可以按下键盘上的“Q”按钮来运行计算器,然后按下“W”按钮来终止它。
PowerShell 可以做到这一点吗?
代码示例:
Add-Type -AssemblyName System.Windows.Forms
function Return-TurnOff
{
$x = Stop-Process -ProcessName calc
$x
}
function Return-TurnOn
{
$x = Start-Process calc
$x
}
$form = New-Object System.Windows.Forms.Form
$form.Text = "Title of the form"
$form.Size = New-Object System.Drawing.Size(300,200)
$form.minimumSize = New-Object System.Drawing.Size(300,200)
$form.maximumSize = New-Object System.Drawing.Size(300,200)
$form.StartPosition = "CenterScreen"
$TurnOffButton = New-Object System.Windows.Forms.Button
$TurnOffButton.Location = New-Object System.Drawing.Point(10,125)
$TurnOffButton.Size = New-Object System.Drawing.Size(55,25)
$TurnOffButton.Text = "Turn Off"
$TurnOffButton.Add_Click({Return-TurnOff})
$form.AcceptButton = $TurnOffButton
$form.Controls.Add($TurnOffButton)
$TurnOnButton = New-Object System.Windows.Forms.Button
$TurnOnButton.Location = New-Object System.Drawing.Point(10,65)
$TurnOnButton.Size = New-Object System.Drawing.Size(55,25)
$TurnOnButton.Text = "Turn On"
$TurnOnButton.Add_Click({Return-TurnOn})
$form.AcceptButton = $TurnOnButton
$form.Controls.Add($TurnOnButton)
$CancelButton = New-Object System.Windows.Forms.Button
$CancelButton.Location = New-Object System.Drawing.Point(215,125)
$CancelButton.Size = New-Object System.Drawing.Size(55,25)
$CancelButton.Text = "Cancel"
$CancelButton.DialogResult = [System.Windows.Forms.DialogResult]::Cancel
$form.CancelButton = $CancelButton
$form.Controls.Add($CancelButton)
$label = New-Object System.Windows.Forms.Label
$label.Location = New-Object System.Drawing.Point(10,15)
$label.Size = New-Object System.Drawing.Size(280,20)
$label.Text = "Label for textbox:"
$form.Controls.Add($label)
$textBox = New-Object System.Windows.Forms.TextBox
$textBox.Location = New-Object System.Drawing.Point(10,35)
$textBox.Size = New-Object System.Drawing.Size(260,20)
$form.Controls.Add($textBox)
$form.Topmost = $True
$form.Add_Shown({$textBox.Select()})
$result = $form.ShowDialog()
【问题讨论】:
标签: forms powershell button keyboard-shortcuts