单击另一个按钮后如何处理按钮单击

Question

我创建了几个按钮，当用户点击第一个按钮时，第一个按钮的边框变为red，然后只有用户可以点击第二个按钮。

该程序可以记录用户按下的第二个按钮并显示 到控制台。

稍后，我想将第一个按钮的背景更改为第二个按钮的背景。

    box = new ResizeButton[]{
                    (ResizeButton) findViewById(R.id.kotak1),
                    (ResizeButton) findViewById(R.id.kotak2),
                    (ResizeButton) findViewById(R.id.kotak3),
                    (ResizeButton) findViewById(R.id.kotak4),
                    (ResizeButton) findViewById(R.id.kotak5),
                    (ResizeButton) findViewById(R.id.kotak6),
                    (ResizeButton) findViewById(R.id.kotak7),
                    (ResizeButton) findViewById(R.id.kotak8),
                    (ResizeButton) findViewById(R.id.kotak9)
            };

            boxPlay = new int[]{0,0,0,0,0,0,0,0,0};  // This is to identify player 1 or player 2 win


    box[i].setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
            box[currentButton].setImageDrawable(getResources().getDrawable(R.drawable.border_red));
            int changeWith;
            do {
                changeWith = selectedButton();
            }while (changeWith == -1);
            Log.d("TAG", "Change: " + changeWith);
    }

    private int selectedButton() {
            returnCode = -1;
            for(int i = 0; i < box.length;i++){
                final int selected = i;
                box[i].setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {
                        if(boxPlay[selected] == 0)
                            returnCode = selected;
                        else
                            invalidSelect();
                    }
                });
            }
            return returnCode;
    }
}

当我运行此代码时出现错误：

原因：输入调度超时（Waiting because the touched 窗口尚未完成对输入事件的处理 之前交付给它。） 负载：1.68 / 1.09 / 0.72

如何解决这个问题？非常感谢您在此问题上的时间和帮助。

Answer 1

只需在每次单击按钮时在所有按钮中设置默认颜色。 然后在可点击按钮中设置边框颜色后。如下所示

    box[i].setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    setDefualtColor()
                    box[currentButton].setImageDrawable(getResources().getDrawable(R.drawable.border_red));
                    int changeWith;
                    do {
                        changeWith = selectedButton();
                    }while (changeWith == -1);
                    Log.d("TAG", "Change: " + changeWith);
                }


private void setDefualtColor(){
        for(int i = 0; i < box.length;i++){
            box[i].setBackground(ContextCompat.getDrawable(baseActivity, R.drawable.defualt_color));
        }
    }

Answer 2

根据您的代码，如果最后一个按钮！=0，它将返回invalidSelect()，因此返回boxPlay[selected] == 0 时的值。

private int selectedButton() {
        returnCode = -1;
        for(int i = 0; i < box.length;i++){
            final int selected = i;
            box[i].setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if(boxPlay[selected] == 0)
                        return selected;
                    else
                       invalidSelect();
            }
        });
    }
    return returnCode;

希望这可行

Answer 3

• this是添加手柄边框的好方法。

  • 至于第二部分，将按钮视图的实例保存在一个变量中，然后在单击其他按钮时访问它。

       private int[] boxPlay = new int[]{0, 0, 0, 0, 0, 0, 0, 0, 0};  // This is to identify player 1 or player 2 win
    
       private Button lastSelectedbutton = null //to store the current selected button instance to get the drawable and reset the button
    
    
       box[i].setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick (View v){
        //this v is the current selected button view's instance
    
    
        // check here if button this is the second button or first
        if (lastSelectedbutton != null) {
    
    
            //means this is second button
            setUpSecondButton(v, lastSelectedButton);
    
            lastSelectedButton = null;
    
        } else {
    
            box[currentButton].setImageDrawable(getResources()
                    .getDrawable(R.drawable.border_red));
            lastSelectedButton = (Button) v;
            int changeWith;
            do {
                changeWith = selectedButton();
            } while (changeWith == -1);
            Log.d("TAG", "Change: " + changeWith);
    
        }
    
    }
    private void setUpSecondButton (Button secondButton, Button firstButton){
        //copy the drawable to second button and reset first button as per need.
        secondButton.setBackground(firstButton.getBackground())
        firstButton.setBackground(null)
    }
    private int selectedButton () {
        returnCode = -1;
        for (int i = 0; i < box.length; i++) {
            final int selected = i;
            box[i].setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if (boxPlay[selected] == 0)
                        returnCode = selected;
                    else
                        invalidSelect();
                }
            });
        }
        return returnCode;
    }
    
    }
    

Answer 4

XML：

<Button
   android:layout_width="match_parent"
   android:layout_height="wrap_content"
   android:layout_weight="1"
   android:onClick="btn1"/>
<Button
   android:layout_width="match_parent"
   android:layout_height="wrap_content"
   android:layout_weight="1"
   android:onClick="btn2"/>

Java：

public void btn1(View v){
   //perform any task on btn1 click
   btn2(v);//btn2 click on 1st button click
}

public void btn2(View v){
   //perform any task on btn2 click
}

或者您可以通过按钮 id 执行点击

box[i].setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
        box[currentButton].setImageDrawable(getResources().getDrawable(R.drawable.border_red));
        int changeWith;
        do {
            changeWith = selectedButton();
        }while (changeWith == -1);
        Log.d("TAG", "Change: " + changeWith);
        box[i+1].performClick();
        box[6].performClick();//or

}