按钮不起作用请求[重复]

Question

所以我正在为我正在制作的独立游戏制作菜单屏幕。我对 pygame 了解不多，但觉得同时制作游戏和学习会很有趣。但由于某种原因，如果您将鼠标悬停在退出游戏按钮的左侧，它会亮起，我希望将其精确设置为按钮大小。

pygame.init()

white = (255, 255, 255)
black = (0, 0, 0)
button_light = (170, 170, 170)
button_dark = (100, 100, 100)

background = black
window = pygame.display.set_mode((1000, 600))
pygame.display.set_caption("Zero Dark Thirty")
window.fill(background)
pygame.display.flip()

width = window.get_width()
height = window.get_height()

small_font = pygame.font.SysFont('Corbel', 35)
quit_button = small_font.render('Exit Game', True, white)


while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
        if event.type == pygame.MOUSEBUTTONDOWN:
            if width / 2 - 50 <= mouse[0] <= width / 2 + 140 and height / 2 - 8 <= mouse[1] <= height / 2 + 40:
                pygame.quit()
    mouse = pygame.mouse.get_pos()

    if width / 2 - 75 <= mouse[0] <= width / 2 + 140 and height / 2 - 8 <= mouse[1] <= height / 2 + 40:
        pygame.draw.rect(window, button_light, [width / 2 - 80, height / 2 - 10, 150, 40])

    else:
        pygame.draw.rect(window, button_dark, [width / 2 - 80, height / 2 - 10, 150, 40])

    window.blit(quit_button, (width / 2 - 75, height / 2 - 8))
    pygame.display.update()

Answer 1

在检查鼠标是否在按钮上的代码中，它显示width / 2 - 50，但在下面的代码中，它显示width / 2 - 75 尝试使它们相同，如果不起作用，请告诉我.