反序列化 JSON 并返回 C# 中的值？

Question

我正在开发 Xamarin 应用程序，我正在尝试从服务器获取 Json 数据，并且运行良好。

但是，现在我只想读取/查看“邀请”的值。

Json 值：

{"invitation":"http://example.com?c_i=eyJsYWJlbCI6Iklzc3VlciIsImltYWdlVXJsIjpudWxsLCJzZXJ2aWNlRW5kcG9pbnQiOiJodHRwOi8vNTIuNzcuMjI4LjIzNDo3MDAwIiwicm91dGluZ0tleXMiOlsiSE51N0x6MkxoZktONEZEMzM2cWdDNWticWI0dTZWRkt2NERaano4YWc1eHQiXSwicmVjaXBpZW50S2V5cyI6WyI3Sm1MMVhOSHRqSHB2WW1KS3d0ZXM2djltNk5yVUJoZW1ON3J6TnZLcGN0SyJdLCJAaWQiOiIzZjgyNWRkZC0zNjNhLTQ2YzEtYTAxNi0xMjAwY2FhZjRkNTkiLCJAdHlwZSI6ImRpZDpzb3Y6QnpDYnNOWWhNcmpIaXFaRFRVQVNIZztzcGVjL2Nvbm5lY3Rpb25zLzEuMC9pbnZpdGF0aW9uIn0="}

我收到此错误...不知道为什么？

错误信息：

Newtonsoft.Json.JsonSerializationException: 'Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[Osma.Mobile.App.ViewModels.Index.IndexViewModel+RootObject]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.
To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object.
Path 'invitation', line 1, position 14.'

我写的代码.....

班级：

public class ConnectionJson
{
    public string Invitation { get; set; }
}

public class RootObject
{
    public List<ConnectionJson> ConnectionsJson { get; set; }
}

主代码：

   public async Task<List<RootObject>> ConnectionInvitationJson()
        {
            HttpClient hTTPClient = new HttpClient();

            Uri uri = new Uri(string.Format("http://example.com/Connections/CreateInvitationJson"));

            HttpResponseMessage response = await hTTPClient.GetAsync(uri);

            string content = await response.Content.ReadAsStringAsync();
            var Items = JsonConvert.DeserializeObject<List<RootObject>>(content);

            await DialogService.AlertAsync(Items.ToString(), "Connection Invitation Json", "Ok");

            return Items;
        }

Answer 1

您的 Json 只是一个对象。更新代码如下

var json = JsonConvert.DeserializeObject<ConnectionJson>(content);

更新代码后，如果不想更改类结构，可以修改如下逻辑

var Items = new List<RootObject> { new List<ConnectionJson> { json }};