如果应用程序在 ios 中处于活动状态，如何在收到通知时发出声音？

Question

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
     [[NSNotificationCenter defaultCenter] postNotificationName:@"MessageReceived" object:self];

    UIApplicationState state = [application applicationState];
    if (state == UIApplicationStateActive)
    {

//        NSString *cancelTitle = @"Close";
        NSString *showTitle = @"Show";
//        NSString *message = [[userInfo valueForKey:@"aps"] valueForKey:@"alert"];
        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"New Order"
                                                            message:@"You just received new order"
                                                           delegate:self
                                                  cancelButtonTitle:nil
                                                     otherButtonTitles:showTitle, nil];

        UILocalNotification *localNotifcation = [[UILocalNotification alloc] init];
        localNotifcation.userInfo = userInfo;
        localNotifcation.soundName = UILocalNotificationDefaultSoundName;
//        localNotifcation.alertBody = message;
        localNotifcation.fireDate = [NSDate date];
        [[UIApplication sharedApplication] scheduleLocalNotification:localNotifcation];

        [alertView show];

    }
    else {
        //Do stuff that you would do if the application was not active
    }
}

请给我一个解决方案，如果现在使用 x-code 6.3 收到通知，我如何在应用程序运行时发出声音？

Answer 1

添加以下框架

#include <AudioToolbox/AudioToolbox.h>

使用下面的代码 -

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{

    UIApplicationState state = [application applicationState];
    if (state == UIApplicationStateActive)
    {

        SystemSoundID soundID;
        CFBundleRef mainBundle = CFBundleGetMainBundle();
        CFURLRef ref = CFBundleCopyResourceURL(mainBundle, (CFStringRef)@"mySoundName.wav", NULL, NULL);
        AudioServicesCreateSystemSoundID(ref, &soundID);
        AudioServicesPlaySystemSound(soundID);
    }
    else {
        // Push Notification received in the background
    }
}

或者你可以使用系统声音——

AudioServicesPlaySystemSound(1007);

振动 -

AudioServicesPlaySystemSound(kSystemSoundID_Vibrate);

查看here所有声音列表。

Answer 2

您可以手动添加声音文件并在应用处于活动状态时播放。

if ([application applicationState] == UIApplicationStateActive) {
        NSLog(@"active");

      NSString *soundPath = [[NSBundle mainBundle] pathForResource:@"alarm2" ofType:@"wav"];
        NSURL *soundURL = [NSURL fileURLWithPath:soundPath];
        AudioServicesCreateSystemSoundID((__bridge CFURLRef)soundURL, &_mySound);
        AudioServicesPlaySystemSound(self.mySound);
    }

有关更多默认声音，请查看此答案：Playing system sound without importing your own

希望对你有帮助

Answer 3

试试这个代码。将此代码为didReceiveRemoteNotification 放入AppDelegate.m

SystemSoundID soundID;
    CFBundleRef mainBundle = CFBundleGetMainBundle();
    CFURLRef ref = CFBundleCopyResourceURL(mainBundle, (CFStringRef)@"Voicemail.wav", NULL, NULL);
    AudioServicesCreateSystemSoundID(ref, &soundID);
    AudioServicesPlaySystemSound(soundID);

这段代码非常适合我..