【发布时间】:2016-09-29 06:23:23
【问题描述】:
$url = trim("https://svcs.sandbox.paypal.com/AdaptiveAccounts/GetVerifiedStatus"); //Sandbox URL
$API_UserName = "XXXXXXX";
$API_Password = "XXXXXXX";
$API_Signature ="XXXXXXX";
$API_AppID = "APP-80W284485P519543T";
$API_RequestFormat = "NV";
$API_ResponseFormat = "NV";
$bodyparams = array ("requestEnvelope.errorLanguage" => "en_US",
"emailAddress" =>"xxxx@gmail.com",
"firstName" =>"XXX",
"lastName" =>"YYY",
"matchCriteria" => "NAME"
);
$body_data = http_build_query($bodyparams, "", chr(38));
我正在执行上面的代码,但它没有给我任何输出。任何人都可以建议我哪里错了?
如果我使用以下网址
$url = trim("https://svcs.paypal.com/AdaptiveAccounts/GetVerifiedStatus"); //Paypal URL
然后它给了我以下响应
responseEnvelope.timestamp: 2016-09-28T23%3A24%3A41.132-07%3A00
responseEnvelope.ack: Failure
responseEnvelope.correlationId: 192ed30d1b3d7
responseEnvelope.build: 24397612
error(0).errorId: 560022
error(0).domain: PLATFORM
error(0).subdomain: Application
error(0).severity: Error
error(0).category: Application
error(0).message: The+X-PAYPAL-APPLICATION-ID+header+contains+an+invalid+value
error(0).parameter(0): X-PAYPAL-APPLICATION-ID
【问题讨论】:
-
这个
The X-PAYPAL-APPLICATION-ID header contains an invalid value怎么样 -
检查您的
X-PAYPAL-APPLICATION-ID -
@DipanwitaKundu 我正在使用 Sandbox URL 帐户。我没有 Paypal 帐户的 APP-ID
-
但是当您的 ID 无效时会出现错误代码 560022。交叉检查您的沙盒帐户
-
@DipanwitaKundu 我听不懂你。哪个 ID 无效。你能给我修改过的代码吗?我给的。