Symfony/FOS - 将用户 id 变量传递给表单类型

Question

我尝试从 CategoryType 表单中设置字段“作者”的值。我希望它是使用 FOS 包登录的当前用户的用户 ID。

我的 CategoryType 表单：

namespace My\CategoryBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class CategoryType extends AbstractType
{
    private $userId;

    public function __construct(array $userId)
    {
        $this->userId = $userId;
    }

     /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('title')
            ->add('author')
            ->add('content')
        ;
    }

    /**
     * @param OptionsResolverInterface $resolver
     */
    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'My\CategoryBundle\Entity\Category',
            'auteur' => $this->userId
        ));
    }

    /**
     * @return string
     */
    public function getName()
    {
        return 'my_categorybundle_category';
    }
}

还有我的控制器动作：

public function addAction()
{
    $category = new Category;
    $user = $this->get('security.context')->getToken()->getUser(); 
    $userId = $user->getId();

    $form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

    $request = $this->get('request');
    if ($request->getMethod() == 'POST') {
        $form->bind($request);

        if ($form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->persist($category);
            $em->flush();

        return $this->redirect($this->generateUrl('mycategory_voir',
            array('id' => $category->getId())));
        }
    }
    return $this->render('MyCategoryBundle:Category:add.html.twig',
        array(
            'form' => $form->createView(),
        ));
}

我在运行操作时发现了这个错误：

可捕获的致命错误：传递给 My\CategoryBundle\Form\CategoryType::__construct() 的参数 1 必须是一个数组，没有给出，在第 55 行的 /My/CategoryBundle/Controller/CategoryController.php 中调用并在 / 中定义My/CategoryBundle/Form/CategoryType.php 第 13 行

我传递给表单的不是已经是一个数组了吗？

Answer 1

你的问题出在这一行

$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

您不满足My\CategoryBundle\FormCategoryType::__construct() 的合同。在这里，让我们换个角度来看。

$form = $this->get('form.factory')->create(
    new CategoryType(/* You told PHP to expect an array here */)
  , array('author' => $userId)
);

您作为第二个参数发送给Symfony\Component\Form\FormFactory::create() 的数组最终被注入为$options 数组My\CategoryBundle\Form\CategoryType::buildForm()

在我看来，你有几种不同的方法来解决这个问题

1. 更新参数签名并调用 My\CategoryBundle\FormCategoryType::__construct() 来传递/接收整个用户对象（不仅仅是他们的 id - 请记住，此时您正在处理 Doctrine 关系，而不是他们映射的较低级别的外键到）

   namespace My\CategoryBundle\Form;
   
   use My\CategoryBundle\Entity\User; /* Or whatver your User class is */
   use Symfony\Component\Form\AbstractType;
   use Symfony\Component\Form\FormBuilderInterface;
   use Symfony\Component\OptionsResolver\OptionsResolverInterface;
   
   class CategoryType extends AbstractType
   {
       private $author;
   
       public function __construct( User $author )
       {
           $this->author = $author;
       }
   

   和

   $form = $this->get('form.factory')->create(
       new CategoryType(
         $this->get('security.context')->getToken()->getUser()
       )
   );
   

2. 不要将User 注入到类型的构造函数中，让选项来处理它

   namespace My\CategoryBundle\Form;
   
   use Symfony\Component\Form\AbstractType;
   use Symfony\Component\Form\FormBuilderInterface;
   use Symfony\Component\OptionsResolver\OptionsResolverInterface;
   
   class CategoryType extends AbstractType
   {
       private $userId;
   
        /**
        * @param FormBuilderInterface $builder
        * @param array $options
        */
       public function buildForm(FormBuilderInterface $builder, array $options)
       {
           $builder
               ->add('title')
               ->add('author', 'hidden', array('data'=>$options['author']))
               ->add('content')
           ;
       }
   
       /**
        * @param OptionsResolverInterface $resolver
        */
       public function setDefaultOptions(OptionsResolverInterface $resolver)
       {
           $resolver->setDefaults(array(
               'data_class' => 'My\CategoryBundle\Entity\Category'
           ));
       }
   
       /**
        * @return string
        */
       public function getName()
       {
           return 'my_categorybundle_category';
       }
   }
   

3. 甚至懒得把作者放在表单中，让控制器处理它

   $form = $this->get('form.factory')->create(
       new CategoryType()
     , array('author' => $this->get('security.context')->getToken()->getUser() )
   );
   

   和

   if ($request->getMethod() == 'POST') {
       $form->bind($request);
   
       if ($form->isValid()) {
           $category->setAuthor(
             $this->get('security.context')->getToken()->getUser()
           );
           $em = $this->getDoctrine()->getManager();
           $em->persist($category);
           $em->flush();
   
       return $this->redirect($this->generateUrl('mycategory_voir',
           array('id' => $category->getId())));
       }
   }
   

4. 将您的表单类型转换为服务并使用 DI 容器注入安全上下文

   app/config/config.yml

   services:
     form.type.my_categorybundle_category:
       class: My\CategoryBundle\Form\CategoryType
       tags:
         - {name: form.type, alias: my_categorybundle_category}
       arguments: ["%security.context%"]
   

   更新您的类型以接收安全上下文

   namespace My\CategoryBundle\Form;
   
   use Symfony\Component\Security\Core\SecurityContext;
   use Symfony\Component\Form\AbstractType;
   use Symfony\Component\Form\FormBuilderInterface;
   use Symfony\Component\OptionsResolver\OptionsResolverInterface;
   
   class CategoryType extends AbstractType
   {
       private $author;
   
       public function __construct( SecurityContext $security )
       {
           $this->author = $security->getToken()->getUser();
       }
   

   然后在您的控制器中，使用其服务名称创建表单

   $form = $this->get('form.factory')->create('my_categorybundle_category');
   

Answer 2

您当前的代码将数组传递给 create() 方法，而不是您的 CategoryType 构造。

$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

应该是

$form = $this->get('form.factory')->create(new CategoryType(array( 'author' => $userId)));