在请求的方法中访问 SOAP 消息头

Question

编辑：清除消息并添加代码

我用一个基本的 Java 客户端开发了一个基于 jax-ws 的 Web 服务。

我使用 SOAP 处理程序来验证用户。一个在客户端，将 userId 和令牌添加到 SOAP 标头，另一个在服务器端，获取这些信息并使用数据库对用户进行身份验证。

客户端（简化）：

import static modules.auth.AuthClient.userID;
import static modules.auth.AuthClient.token;

public boolean handleMessage(SOAPMessageContext context) {

    //Getting SOAP headers
    SOAPMessage soapMsg = context.getMessage();
    SOAPEnvelope soapEnv = soapMsg.getSOAPPart().getEnvelope();
    SOAPHeader soapHeader = soapEnv.getHeader();

    QName qname;
    SOAPHeaderElement soapHeaderElement;

    //Add userID in SOAP header
    qname = new QName("****","UserID");
    soapHeaderElement = soapHeader.addHeaderElement(qname);
    soapHeaderElement.setActor(SOAPConstants.URI_SOAP_ACTOR_NEXT);
    soapHeaderElement.addTextNode(userID);

    //Add token in SOAP header
    qname = new QName("****","Token");
    soapHeaderElement = soapHeader.addHeaderElement(qname);
    soapHeaderElement.setActor(SOAPConstants.URI_SOAP_ACTOR_NEXT);
    soapHeaderElement.addTextNode(token);

    soapMsg.saveChanges();

    return true;
}

服务器端（简化）：

public boolean handleMessage(SOAPMessageContext context) {  
    Boolean isRequest = (Boolean) context.get(MessageContext.MESSAGE_OUTBOUND_PROPERTY);

    if (!isRequest) {
        //Getting SOAP headers
        SOAPMessage soapMsg = context.getMessage();
        SOAPEnvelope soapEnv = soapMsg.getSOAPPart().getEnvelope();
        SOAPHeader soapHeader = soapEnv.getHeader();

        Iterator it = soapHeader.extractHeaderElements(SOAPConstants.URI_SOAP_ACTOR_NEXT);

        Node userIDNode = (Node) it.next();
        String userID = (userIDNode == null) ? null : userIDNode.getValue();

        Node tokenNode = (Node) it.next();
        String token = (tokenNode == null) ? null : tokenNode.getValue();

        //Return if the user is connected
        User u = AuthWS.validToken(userID, token);

        //Here I have my user but I don't know how to get it in my requested method
    }
    return true;
}

为了管理用户权限，我想直接在请求的方法中访问我的用户。

可以请求的方法示例：

public Project getProject(@WebParam(name = "name") String name) throws WebServiceFailure, EntityNotFoundException {

    //Here I would like to verify the user's rights

    try {
        PreparedStatement ps = DBConnect.getStatement("SELECT name FROM projects WHERE name = '" + name + "'");
        ResultSet res = ps.executeQuery();
        if(res.next()){
            Project p = new Project(res.getString("name"));
            ps.close();
            return p;
        } else {
            ps.close();
            throw new EntityNotFoundException("Can't find the project '"+name+"'");
        }
    } catch (SQLException ex) {
        throw new WebServiceFailure(ex.getMessage());
    }
}

非常感谢

Answer 1

最后，我找到了我正在寻找的东西：

Follow this link.

在“将信息从处理程序级别传递到应用程序”部分中