【问题标题】:Swift IP Address from NSNetService来自 NSNetService 的 Swift IP 地址
【发布时间】:2026-02-08 16:00:02
【问题描述】:

我可以在我的 Swift 项目中使用 Objective-C 代码从 NSNetService 获取 IP 地址。是否有 Swift 代码可以做同样的事情(以避免出现桥接头)?否则我会保持我现在的方式 - 但希望它可以在 Swift 中完成。

-(NSString* )IPAddressesFromData:(NSNetService *)service {
    for (NSData *address in [service addresses]) {
        struct sockaddr_in *socketAddress = (struct sockaddr_in *) [address bytes];
        //NSLog(@"Service name: %@ , ip: %s , port %i", [service name], inet_ntoa(socketAddress->sin_addr), [service port]);
        NSString *retString = [NSString stringWithFormat:@"%s", inet_ntoa(socketAddress->sin_addr)];
        return retString;
    }
    return @"Unknown";
}

更新的代码有效:

func netServiceDidResolveAddress(sender: NSNetService) {
    let theAddress = sender.addresses!.first! as NSData
    var hostname = [CChar](count: Int(NI_MAXHOST), repeatedValue: 0)
    if getnameinfo(UnsafePointer(theAddress.bytes), socklen_t(theAddress.length),
                   &hostname, socklen_t(hostname.count), nil, 0, NI_NUMERICHOST) == 0 {
        if let numAddress = String.fromCString(hostname) {
            print("Resolved IP address: \(numAddress)")
        }
    }
}

【问题讨论】:

  • 查看*.com/questions/25890533/…,了解如何从 sockaddr 结构中获取 IP 字符串。
  • 沙赞!非常感谢 - 我将使用更新后的代码编辑我的原始问题。

标签: objective-c swift ip-address nsnetservice


【解决方案1】:

你可以使用:

func netServiceDidResolveAddress(_ sender: NetService) {

    var hostname = [CChar](repeating: 0, count: Int(NI_MAXHOST))
    guard let data = sender.addresses?.first else { return }
    do {
        try data.withUnsafeBytes { (pointer:UnsafePointer<sockaddr>) -> Void in
            guard getnameinfo(pointer, socklen_t(data.count), &hostname, socklen_t(hostname.count), nil, 0, NI_NUMERICHOST) == 0 else {
                throw NSError(domain: "domain", code: 0, userInfo: ["error":"unable to get ip address"])
            }
        }
    } catch {
        print(error)
        return
    }
    let address = String(cString:hostname)
    print("\(sender.name)  IP:\(address)")

}

【讨论】: