发送 get 请求时不带括号返回

Question

我的 api 返回以下 json：

{
    "requestInfo": [
        {
            "requestId": 118170,
            "firstRead": "1905-06-24T00:00:00",
            "requestAnswerSent": "2021-09-09T00:00:00",
            "currentMilage": "13131",
            "damageOccured": "1753-01-01T00:00:00",
            "milageDamageOccured": 0,
            "latestService": "1753-01-01T00:00:00",
            "latestServiceKm": 0,
            "contractID": 00000,
            "requestRecieved": "2021-10-08T16:18:58.237",
            "requestStatus": "NEW_REQUEST",
            "claiminfo": [
                {
                    "claimId": 387498,
                    "name": "Claim",
                    "answerSent": "2021-09-09T00:00:00"
                },
                {
                    "claimId": 387499,
                    "name": "Rent Replacement Car",
                    "answerSent": "2021-09-09T00:00:00"
                },
                {
                    "claimId": 387500,
                    "name": "Other Work",
                    "answerSent": "2021-09-09T00:00:00"
                }
            ]
        }
    ]
}

而且我想返回它而不用括号括起来。我不能使用任何FOR JSON WITHOUT WRAPPER，因为我返回了一个列表，正如您在"claiminfo" 中看到的那样，但我仍然想返回而不将它包裹在{ } 中。 再次由于返回列表，我也不能使用SingleOrDefault 之类的东西。这是代码（方法、模型和控制器）

public class RequestInfo
    {
        //public int claimId { get; set; } = 0;
        public int requestId { get; set; } = 0;
        public DateTime firstRead { get; set; } = DateTime.Parse("1753-01-01");
        public DateTime requestAnswerSent { get; set; } = DateTime.Parse("2021-09-09");
        public string currentMilage { get; set; } = "";
        public DateTime damageOccured { get; set; } = DateTime.Parse("1753-01-01");
        public int milageDamageOccured { get; set; } = 0;
        public DateTime latestService { get; set; } = DateTime.Parse("1753-01-01");
        public int latestServiceKm { get; set; } = 0;
        public int contractID { get; set; } = 0;
        public DateTime requestRecieved { get; set; } = DateTime.Parse("1753-01-01");
        public string requestStatus { get; set; } = "";
        public IEnumerable<ClaimInfo> claiminfo { get; set; }
    }

    public class ClaimInfo
    {
        public int claimId { get; set; } = 0;
        public string name { get; set; } = "";
        public DateTime answerSent { get; set; } = DateTime.Parse("2021-09-09");
    }

    public class RequestInformation
    {
        public IEnumerable<RequestInfo> requestInfo { get; set; }
    }

这是控制器：

[HttpGet]
        public async Task<IActionResult> getRequestInfo([FromQuery] RequestInfo model)
        {

        if (!ModelState.IsValid)
        {
            return BadRequest(ModelState);
        }
        try
        {
            var list = await _request.getRequestInfo(model);
            return Ok(list);
        }
        catch (Exception ex)
        {
            return BadRequest(ex.Message);
        }
        return Ok();
    }

最后是方法：

// request info card 
public async Task<RequestInformation> getRequestInfo(RequestInfo model)
{
    var parameters = new DynamicParameters();
    parameters.Add("@requestId", model.requestId);
    var getAllRequest = await _sqlconnection.QueryAsync<RequestInfo>($@"SELECT TOP 1
    Request.ID as requestId, 
    FirstRead as firstRead,
    CurrentKilometerreading as currentMilage, 
    DamageDate as damageOccured, DamageKilometerreading as milageDamageOccured,
    LatestServiceDate as latestService, LatestServiceKilometer as latestServiceKm,
    ClaimHandlingStatus.Name as requestStatus, Request.CreatedDate as requestRecieved, 
    Contract.ID as contractID
    FROM Request 
    INNER JOIN RequestCrossClaim ON Request.ID = RequestCrossClaim.RequestID
    INNER JOIN Claim ON RequestCrossClaim.ClamID = Claim.ID
    INNER JOIN Contract ON Request.ContractID = Contract.ID
    INNER JOIN ClaimHandlingStatus ON Request.ClaimHandlingStatusID = 
    ClaimHandlingStatus.ID
    WHERE Request.ID = @requestId", parameters);


    var getClaimsForRequet = await _sqlconnection.QueryAsync<ClaimInfo>($@"
    SELECT RequestType.Name, AnswerSent, Claim.ID as claimId
    FROM Request
    INNER JOIN RequestCrossClaim ON Request.ID = RequestCrossClaim.RequestID
    INNER JOIN Claim ON RequestCrossClaim.ClamID = Claim.ID
    INNER JOIN RequestType ON RequestTypeID = RequestType.ID
    WHERE Request.ID = @requestId", parameters);

    var claims = getClaimsForRequet;
    var request = new RequestInformation()
    {
        requestInfo = getAllRequest
    };

    foreach (var r in request.requestInfo)
    {
        r.claiminfo = claims.OrderBy(s => s.claimId);
    }

    return request;
}

感谢您的帮助。

Answer 1

在 getRequestInfo 中尝试返回 OK(list.requestInfo) 而不是 OK(list)。意思是，从结果（列表）中提取对象 requestInfo。