foreach (xmlNode) 只插入第一个值

Question

我正在尝试使用 Web 服务将 MS Infopath 重复表中的值插入到 SQL server DB 中，但根据行数，只有第一个值会被插入和复制。

信息路径

SQL Server 数据库

代码

[WebMethod]
public void SubmitDocument(XmlDocument doc)
{
    string firstname;
    string lastname;

    XmlNamespaceManager nsManager = new XmlNamespaceManager(doc.NameTable);
    nsManager.AddNamespace("my", "http://schemas.microsoft.com/office/infopath/2003/myXSD/2018-08-16T17:55:49");
    nsManager.AddNamespace("dfs", "http://schemas.microsoft.com/office/infopath/2003/dataFormSolution");

    XmlNode root = doc.DocumentElement;
    XmlNodeList list = root.SelectNodes("/dfs:IPDocument/my:myFields/my:UserList/my:Users", nsManager);

    foreach (XmlNode node in list)
    {
        firstname = node.SelectSingleNode("/dfs:IPDocument/my:myFields/my:UserList/my:Users/my:FirstName", nsManager).InnerText;
        lastname = node.SelectSingleNode("/dfs:IPDocument/my:myFields/my:UserList/my:Users/my:LastName", nsManager).InnerText;

        SubmitToDatabase(firstname, lastname);
    }
}

public void SubmitToDatabase(string firstname, string lastname)
{
    try
    {
        using (SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["conn"].ConnectionString))
        {
            SqlCommand cmd = new SqlCommand("INSERT INTO infopathconcepttable(FirstName, LastName)VALUES(@FirstName,@LastName)", conn);

            cmd.Parameters.AddWithValue("@FirstName", firstname);
            cmd.Parameters.AddWithValue("@LastName", lastname);

            conn.Open();
            cmd.ExecuteNonQuery();
            conn.Close();
        }
    }
    catch (SqlException ex)
    {

    }
}

Answer 1

我相信这与在您的 SelectSingleNode() 调用中提供绝对 XPath 表达式有关。

尝试使用以下行替换两个 SelectSingleNode() 调用：

firstname = node["FirstName", nsManager.LookupNamespace("my")].InnerText;
lastname = node["LastName", nsManager.LookupNamespace("my")].InnerText;

Answer 2

考虑到您已经访问了 XmlNodeList，您无需在循环中重新指定要获取的节点。 如果您确定不会在源代码中获得 null 值，则类似以下内容应该会为您提供预期的结果：

foreach (XmlNode node in list)
{
    firstname = node.SelectSingleNode("FirstName").InnerText;
    lastname = node.SelectSingleNode("LastName").InnerText;

    SubmitToDatabase(firstname, lastname);
}

您还可以通过索引从节点列表中访问节点：

firstname = node["FirstName"].InnerText;
lastname = node["LastName"].InnerText;