【发布时间】:2015-04-21 10:42:22
【问题描述】:
我正在使用 jsp 将表单发送到 servlet。在服务器端处理完成,然后我想向用户发出警报,通知他是否成功。问题是我没有得到任何警报,但也没有例外。当帖子结束时,我看到(虽然我不想)浏览器 url 上的表单值就像 get.... 这是代码
<form id="register" class="form-signin" >
<h2 class="form-signin-heading">Register here</h2>
First Name:<input type="text" name="firstName" class="input-block-level" placeholder="user name" required><br>
Last Name:<input type="text" name="lastName" class="input-block-level" placeholder="user name" required><br>
User Name:<input type="text" name="user" class="input-block-level" placeholder="user name" required><br>
Password:<input type="password" name="password" class="input-block-level" placeholder="Password" required><br>
Retype Password:<input type="password" name="retypedPassword" class="input-block-level" placeholder="Password" required><br>
Email:<input type="email" name="email" class="input-block-level" placeholder="email required"><br>
Retype Email:<input type="email" name="retypedEmail" class="input-block-level" placeholder="email required"><br>
<input type="submit" value="submit" id="submitButton" class="btn btn-primary">
</form>
<script type="text/javascript">
$(document).ready(function(){
$("#submitButton").on("click", function(){
$.ajax({
type: "POST",
url: "RegisterServlet", //process to mail
data: $("#register").serialize(),
success: function(msg){
alert(msg);
},
error: function(){
alert("failure editing account. User name already taken");
}
});
});
});
</script>
在服务器端
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String firstName = request.getParameter("firstName");
String lastName = request.getParameter("lastName");
String username = request.getParameter("user");
String password = request.getParameter("password");
String retypedPassword = request.getParameter("retypedPassword");
String email =request.getParameter("email");
String retypedEmail = request.getParameter("retypedEmail");
String hash = UUID.randomUUID().toString();
if(firstName == null || firstName.equals("")){
errorMsg = "First name can't be null or empty.";
}
if(lastName == null || lastName.equals("")){
errorMsg = "Last name can't be null or empty.";
}
if(username == null || username.equals("")){
errorMsg = "User name can't be null or empty.";
}
if(password == null || password.equals("")){
errorMsg = "Password can't be null or empty.";
}
if(retypedPassword == null || retypedPassword.equals("")){
errorMsg = "Retype password can't be null or empty.";
}
if(email == null || email.equals("")){
errorMsg = "Email can't be null or empty.";
}
if(retypedEmail == null || retypedEmail.equals("")){
errorMsg = "Retyped email can't be null or empty.";
}
if(password.equals(retypedPassword)==false){
errorMsg = "Passwords do not match.";
}
if(retypedEmail.equals(email)==false){
errorMsg = " Emails are not the same.";
}
if(errorMsg != null){
response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
response.setCharacterEncoding("UTF-8");
response.getWriter().write(errorMsg);
}
但即使我尝试,我什么也得不到。这段代码有什么问题?为什么提交后我看到url上的参数??
【问题讨论】:
-
尝试在客户端和服务器端添加日志。调试流程。你会知道它在哪里坏了。
-
您应该防止表单提交的默认行为。例如,通过在
click函数的末尾添加return false;。