Unity中角色跳跃时如何禁用重力？

Question

我正在 Unity3d 中开发一个无尽的跑步游戏，我遇到了这个问题。我已经让我的角色跳跃，在这样做的过程中，我使用了 Unity 中的曲线功能来改变跳跃时的角色高度和中心。

然后我遇到了这个问题。当我按下跳转按钮时，我使动画剪辑以没有向上推力或任何物理的方式运行。只是我正在减少对撞机的高度和中心点。但这样做时，我的角色往往会因为我实施了重力而下降，因为最终我的角色应该会下降。

我唯一不想涉及重力的情况是我在跳跃时（跳跃动画正在运行时）。我该怎么做呢。或有关如何解决此错误的任何建议？

下面是我为跳跃实现的代码。

private float verticalVelocity;
public float gravity = 150.0f;
private bool grounded = true;
private bool jump = false;
private float currentY;

private Animator anim;
private AnimatorStateInfo currentBaseState;

private static int fallState = Animator.StringToHash("Base Layer.Fall");
private static int rollState = Animator.StringToHash("Base Layer.Roll");
private static int locoState = Animator.StringToHash("Base Layer.Run");
private static int jumpState = Animator.StringToHash("Base Layer.Jump");

private void Update()
{
    currentY = verticalVelocity * Time.fixedDeltaTime;
    currentBaseState = anim.GetCurrentAnimatorStateInfo(0);
    grounded = true;

    if (isGround() && currentY < 0f)
    {
        verticalVelocity = 0f;
        currentY = 0f;
        grounded = true;
        jump = false;
        fall = false;

        if (currentBaseState.fullPathHash == locoState)
        {

            if (Input.GetButtonDown("Jump") && grounded && currentY == 0f)
            {

                grounded = false;
                jump = true;
                verticalVelocity = 0f; //I have tried here to stop gravity but don't work
                follower.motion.offset = new Vector2(follower.motion.offset.x, verticalVelocity);
            }
        }
        else if (currentBaseState.fullPathHash == jumpState)
        {
            Debug.Log("Jumping state");
            collider.height = anim.GetFloat("ColliderHeight");
            collider.center = new Vector3(0f, anim.GetFloat("ColliderY"), 0f);
        }
    }
    else if (jump)
    {
        follower.motion.offset = new Vector2(follower.motion.offset.x, 0.0f); //I have tried here to stop gravity but don't work
    }
    else
    {
        grounded = false;
        jump = false;
        fall = true;
    }

    anim.SetBool("Grounded", grounded);
    anim.SetBool("Jump", jump);
    anim.SetBool("Fall", fall);

    if (fall)
    {
        if (currentBaseState.fullPathHash == fallState)
        {
            Debug.Log("falling");
            collider.height = anim.GetFloat("ColliderHeight");
            collider.center = new Vector3(0f, anim.GetFloat("ColliderY"), 0f);
        }
    }
    else
    {
        if (currentBaseState.fullPathHash == rollState)
        {
            Debug.Log("Roll");
            collider.height = anim.GetFloat("ColliderHeight");
            collider.center = new Vector3(0f, anim.GetFloat("ColliderY"), 0f);
        }
    }

    MoveLeftRight();
    verticalVelocity -= gravity * Time.fixedDeltaTime;
    follower.motion.offset = new Vector2(follower.motion.offset.x, currentY);

    Z - Forward and Backward
    follower.followSpeed = speed; 
} 

Answer 1

在角色选项中，当您选择对象时，应该有一个选项可以禁用它的物理特性。

编辑：它在rigidbody.useGravity下

https://docs.unity3d.com/ScriptReference/Rigidbody-useGravity.html

Answer 2

要以编程方式禁用场景的重力，您可以使用：

if (isGrounded)
{
    Physics.gravity = new Vector3(0, -9.8f, 0);
} else {
    // Here the value you prefer
    Physics.gravity = new Vector3(0, -0.1f, 0);
}

但是通过这种方法，场景中的其他元素也不会受到重力的影响，我不确定你是否想要这个。

所以要禁用特定游戏对象的重力，您可以编写：

rb = GetComponent<Rigidbody>();
rb.useGravity = false;

另一个选项（我从未尝试过 myelf）是：在游戏对象上施加一个力来补偿重力（y 轴上应该是 -9.8f）

private void Start()
{
    rb = GetComponent<Rigidbody>();
}
private void FixedUpdate()
{
    rb.AddForce(transform.down * 9.8f);
}

或者也许用恒力：

GetComponent<ConstantForce>().force = new Vector3(0, 9.8f, 0);

https://docs.unity3d.com/Manual/class-ConstantForce.html