我的Java代码中的逻辑错误......在开关情况下

Question

package com.company;

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner myScanner = new Scanner(System.in);
        int operator;
        double number1, number2, result;
        boolean ask = true;
        while (ask) {

        System.out.println("please select your operator:\n"
                + "1 for +\n" +
                "2 for -\n" +
                "3 for *\n" +
                "4 for %\n" +
                "");
        operator = myScanner.nextInt();
        System.out.println("you chose " + operator + " operator babe");


            System.out.println("please enter your first number");
            Scanner numberScanner = new Scanner(System.in);
            number1 = numberScanner.nextDouble();
            System.out.println("please enter your second number");
            Scanner numberScanner2 = new Scanner(System.in);
            number2 = numberScanner2.nextDouble();


            switch (operator) {
                case 1:
                    result = number1 + number2;
                    System.out.println("result is:" + result);
                    break;
                case 2:
                    result = number1 - number2;
                    System.out.println("result is:" + result);
                    break;
                case 3:
                    result = number1 * number2;
                    System.out.println("result is:" + result);
                    break;
                case 4:
                    result = number1 / number2;
                    System.out.println("result is:" + result);
                    break;
                default:
                    System.out.println("you chosen the wrong operator babe :)");
                    break;
            }


            System.out.println("do yo want to continue?\n" +
                    "y for yes\n" +
                    "n for no\n");
            char askInput = myScanner.next().charAt(0);
            if (askInput=='n') ask=false;
        }
    }
}

我的开关盒出了问题
如果我按任何数字或字母，如 5 或 6 或...它应该打印 you chose wrong operator。

我认为问题在于我的默认设置，但我不知道问题在哪里？

Answer 1

只需像这样重新排序您的代码

`public static void main(String[] args) {
    Scanner myScanner = new Scanner(System.in);
    int operator;
    double number1, number2, result;
    boolean ask = true;
    while (ask) {
        System.out.println("please enter your first number");
        Scanner numberScanner = new Scanner(System.in);
        number1 = numberScanner.nextDouble();
        System.out.println("please enter your second number");
        Scanner numberScanner2 = new Scanner(System.in);
        number2 = numberScanner2.nextDouble();

        System.out.println("please select your operator:\n"
                + "1 for +\n"
                + "2 for -\n"
                + "3 for *\n"
                + "4 for %\n"
                + "");
        operator = myScanner.nextInt();

        switch (operator) {
            case 1:
                result = number1 + number2;
                System.out.println("result is:" + result);
                break;
            case 2:
                result = number1 - number2;
                System.out.println("result is:" + result);
                break;
            case 3:
                result = number1 * number2;
                System.out.println("result is:" + result);
                break;
            case 4:
                result = number1 / number2;
                System.out.println("result is:" + result);
                break;
            default:
                System.out.println("you chosen the wrong operator babe :)");
                break;
        }
        System.out.println("you chose " + operator + " operator babe");

        System.out.println("do yo want to continue?\n"
                + "y for yes\n"
                + "n for no\n");
        char askInput = myScanner.next().charAt(0);
        if (askInput == 'n') {
            ask = false;
        }
    }
}`

你会没事的

Answer 2

至于我的评论，如果您想在让用户输入另外 2 个数字之前验证用户所做的输入（对于选项），那么，是的，您实际上应该这样编程，即验证在第一个数字之后进行用户输入。这是您的代码稍作修正的版本。

public static void main(String[] args) {
    int operator;
    double result;
    boolean ask = true;
    Scanner numberScanner = new Scanner(System.in);
    while (ask) {

        System.out.println(
                "please select your operator:\n" + "1 for +\n" + "2 for -\n" + "3 for *\n" + "4 for %\n" + "");
        operator = numberScanner.nextInt();
        System.out.println("you chose " + operator + " operator babe");

        // Here was your "Mistake". You instantly started asking the user for another input,
        // but actually wanted to ahve the switch statment here

        switch (operator) {
        case 1:
            result = get_num1(numberScanner) + get_num2(numberScanner);
            System.out.println("result is:" + result);
            break;
        case 2:
            result = get_num1(numberScanner) - get_num2(numberScanner);
            System.out.println("result is:" + result);
            break;
        case 3:
            result = get_num1(numberScanner) * get_num2(numberScanner);
            System.out.println("result is:" + result);
            break;
        case 4:
            result = get_num1(numberScanner) % get_num2(numberScanner);
            System.out.println("result is:" + result);
            break;
        default:
            System.out.println("you chosen the wrong operator babe :)");
            break;

        }

        System.out.println("do yo want to continue?\n" + "y for yes\n" + "n for no\n");
        char askInput = numberScanner.next().charAt(0);
        if (askInput == 'n')
            ask = false;
    }
}

public static double get_num1(Scanner scanner) {
    System.out.println("please enter your first number");
    return scanner.nextDouble();
}

public static double get_num2(Scanner scanner) {
    System.out.println("please enter your second number");
    return scanner.nextDouble();
}

Answer 3

您可以在分配输入时验证运算符。

例如使用 if 条件并检查它是否在 1 和 5 之间，如果不打印你想要的任何内容

Answer 4

两件事：

你不需要两台扫描仪，只用一台就足够了

代码之所以如此，是因为您在询问要操作的数字后进入开关盒...

一些条件，例如：

operator = myScanner.nextInt();
if (operator < 1 || operator > 4) {

 }

可能有帮助....