在开关盒上放置一个循环。用户选择选项 5 时退出菜单

Question

我有一个包含 5 个案例的 switch 案例，每个案例都有不同的任务要做。我想这样做，以便当用户选择案例选项并且任务由程序完成时，菜单再次出现，用户可以继续从菜单中选择某些内容，直到用户选择退出的菜单选项 5。

目前为止：

//sys.out to print the menu options

            System.out.print("Enter the number of your choosing: ");
            menu = scan.nextInt();
            System.out.println();


            switch (menu) {

            case 1:
            //code
            break;
            case 2:
            //code
            break;
            case 3:
            //code
            break;
            case 4:
            //code
            break;
            case 5:
            //code
            break;
            case 12:
            System.exit(0);
            break;
    }

Answer 1

怎么样：

int menu = 0;
//you already said it: "the user can keep choosing something from 
//the menu until the user choses menu option 5"
while(menu != 5) {

    System.out.print("Enter the number of your choosing: ");
    menu = scan.nextInt();
    System.out.println();

    switch(menu){
        case 1: ...
        ...
        case 5: 
           break;
        default: System.out.println("Not supported.");
           break;
    }
}

//exit...

Answer 2

public int getItem ()
{
    int item = 0;
    do
    {
        System.out.println("Enter");
        item = scanner.nextInt();
        scanner.nextLine();
    }
    while (item < 0 || item > 5);
    return item;
}

public void start ()
{
    int item;
    show ();
    item = getItem();
    switch (item)
        {
            case 1: code    break;
            .......
            case 5: code    break;
         }
    while (item !=0)
        System.out.println("buye");