【发布时间】:2015-03-22 19:48:51
【问题描述】:
编辑:
我从字典中问用户一组问题:
questions = {
"strong": "Do ye like yer drinks strong? ",
"salty": "Do ye like it with a salty tang? ",
"bitter": "Are ye a lubber who likes it bitter? ",
"sweet": "Would ye like a bit of sweetness with yer poison? ",
"fruity": "Are ye one for a fruity finish? "
}
这些键与另一个字典相关联:
ingredients = {
"strong": ["glug of rum", "slug of whiskey", "splash of gin"],
"salty": ["olive on a stick", "salt-dusted rim", "rasher of bacon"],
"bitter": ["shake of bitters", "splash of tonic", "twist of lemon peel"],
"sweet": ["sugar cube", "spoonful of honey", "splash of cola"],
"fruity": ["slice of orange", "dash of cassis", "cherry on top"]
}
我通过为每个问题设置的“简单”if/elif 向他们提问,并将他们的答案分配给新字典:
beverage = {}
def drink():
"""Find out user preferences and assign to new dictionary"""
if raw_input(questions["strong"]).lower() == "yes":
beverage["strong"] = ingredients["strong"]
elif raw_input(questions["strong"]).lower() == "no":
return False
if raw_input(questions["salty"]).lower() == "yes":
beverage["salty"] = ingredients["salty"]
elif raw_input(questions["salty"]).lower() == "no":
return False
...
drink()
最后打印饮料:
print beverage
如果用户说“是”,则一切正常。
但是,如果用户回答“否”,则会再次询问第一个问题(可能是因为我使用 raw_input() 的 if/elif 结构),然后跳过完成脚本的所有其他问题。
如何构建它,以便如果用户对第一个问题说“不”,它会问下一个问题而不是每个问题两次?
打印输出:
Do ye like yer drinks strong? yes
Do ye like it with a salty tang? no
Do ye like it with a salty tang? yes
Are ye a lubber who likes it bitter? no
Are ye a lubber who likes it bitter? yes
Would ye like a bit of sweetness with yer poison? no
Would ye like a bit of sweetness with yer poison? yes
Are ye one for a fruity finish? no
Are ye one for a fruity finish? yes
Yer cocktail is a made of a
['glug of rum']
【问题讨论】:
-
or "yes"表示如果 "yes" == True 并且 "yes" 始终为 True -
我应该为每个问题使用单独的函数吗?
标签: python function if-statement dictionary return