Python - 一个单词中有多个字母的刽子手游戏

Question

我是 python 新手，并且对我正在制作的刽子手游戏有疑问。所以我有一个名为“当前”的列表，其中包含连字符 (-) 的次数与人们猜测的单词的长度相同。当他们正确猜出一个字母时，它会将连字符替换为正确位置的字母。我遇到的问题是，如果一个单词中有 2 个或更多相同的字母，那么它在第一次出现该字母时有效，但之后它会说该字母已经被猜到，因此它不起作用，我无法弄清楚如何解决此问题。

current = "_" * len(theword)
x = list(current)
print (x)

guessed = []

while current != theword and lives > 0:

    print ("You have %d lives left" % lives)
    guess = input("Please input one letter or type 'exit' to quit.")
    guess = guess.lower()


    if guess == "exit":
        break
    elif guess in guessed:

        print ("You have already guessed this letter, please try again.")



    guessed.append(guess)

    if guess in theword:
        index = theword.find(guess)
        x = list(current)
        x[index] = guess
        current = "".join(x)
        print ("Correct! \nYour guesses: %s" % (guessed))
        print(x)


    else:
        print ("Incorrect, try again")
        lives = lives -1


if current == theword:
    print ("Well done, you have won!")

谢谢

Answer 1

通过使用 string.find 方法，您只能获得单词中第一次出现的字符。通过定义这个方法，你可以得到所有的出现：

def find_all(word, guess):
    return [i for i, letter in enumerate(word) if letter == guess]

你还应该在检查你之前是否已经猜到这个字母之后添加一个“继续”，这样你就不会再次将它添加到列表中。

这应该可行：

def find_all(word, guess):
    return [i for i, letter in enumerate(word) if letter == guess]

current = "_" * len(theword)
x = list(current)
print (x)

guessed = []

while current != theword and lives > 0:

    print ("You have %d lives left" % lives)
    guess = input("Please input one letter or type 'exit' to quit.")
    guess = guess.lower()


    if guess == "exit":
        break
    elif guess in guessed:
        print ("You have already guessed this letter, please try again.")
        continue

    guessed.append(guess)

    if guess in theword:
        indices = find_all(theword, guess)
        x = list(current)
        for i in indices:
            x[i] = guess
            current = "".join(x)
            print ("Correct! \nYour guesses: %s" % (guessed))
            print(x)

    else:
        print ("Incorrect, try again")
        lives = lives -1

Answer 2

代替：

if guess in theword:
        index = theword.find(guess)
        x = list(current)
        x[index] = guess
        current = "".join(x)
        print ("Correct! \nYour guesses: %s" % (guessed))
        print(x)

试试这个：

for index,character in enumerate(theword):
    x = list(current)
    if character == guess:
        x[index] = guess