合并具有相同属性值的json对象c#

Question

如何在具有相同键和值的同一响应中组合 JSON 对象。就像我有两个具有相同语言的对象：Python 我想将它们组合起来并列出该语言下的剩余数据 Python 我不希望它被重复

[
  [
    {
      "language": "Python",
      "id": 319029846,
      "full_Name": "beurtschipper/Depix",
      "name": "Depix"
    },
    {
      "language": "Python",
      "id": 319169382,
      "full_Name": "benwilber/boltstream",
      "name": "boltstream"
    },
    {
      "language": "Python",
      "id": 316899719,
      "full_Name": "r0ysue/r0capture",
      "name": "r0capture"
    }
  ],
  [
    {
      "language": "YARA",
      "id": 318029147,
      "full_Name": "fireeye/red_team_tool_countermeasures",
      "name": "red_team_tool_countermeasures"
    }
  ],
  [
    {
      "language": "TypeScript",
      "id": 313443335,
      "full_Name": "pmndrs/valtio",
      "name": "valtio"
    }
  ]
]

我想要的形式是什么

[
  [
    {
      "language": "Python",
      "id": [319029846, 319169382, 316899719],
      "full_Name": ["beurtschipper/Depix", "benwilber/boltstream", "r0ysue/r0capture"],
      "name": ["Depix", "boltstream", "r0capture"]
    }
  ],
  [
    {
      "language": "YARA",
      "id": 318029147,
      "full_Name": "fireeye/red_team_tool_countermeasures",
      "name": "red_team_tool_countermeasures"
    }
  ],
  [
    {
      "language": "TypeScript",
      "id": 313443335,
      "full_Name": "pmndrs/valtio",
      "name": "valtio"
    }
  ]
]

这是我正在使用的代码

    public class Items
    {
        [JsonPropertyName("language")]
        public string Language { get; set; }
        [JsonPropertyName("id")]
        public int Id { get; set; }

        [JsonPropertyName("name")]
        public  string Name { get; set; }

        [JsonPropertyName("full_name")]
        public string Full_Name { get; set; }
        public string total_count { get; set; }
    }

    public class Root
    {
        [JsonPropertyName("items")]
        public List<Items> Items { get; set; }
    }


        Root jObj2 = JsonConvert.DeserializeObject<Root>(readerResult);
        var result = jObj2.Items.Select(x => new
        {
            x.Language,
            x.Id,
            x.Full_Name,
            x.Name
        }).GroupBy(x => x.Language).ToArray();
        return new JsonResult(result);

Answer 1

GroupBy 是一个很好的起点。获得组后，您需要将每个组的各个属性选择到一个新列表中：

var result = jObj2.Items
    .GroupBy(x => x.Language)
    .Select(group => new
    {
        Language = group.Key,
        Ids = group.Select(x => x.Id).ToList(),
        FullNames = group.Select(x => x.Full_Name).ToList(),
        Names = group.Select(x => x.Name).ToList()
    })
    .ToArray();