Firebase 错误：进程以代码 16 退出进程。<匿名>

Question

我不断收到此错误，不太确定发生了什么。

queueFunction
Error: Process exited with code 16
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:275:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at process.exit (internal/process/per_thread.js:167:15)
at Object.sendCrashResponse (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/logger.js:37:9)
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:271:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at processPromiseRejections (internal/process/promises.js:209:33)
at processTicksAndRejections (internal/process/task_queues.js:98:32)

queueMatch
Error: Process exited with code 16
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:275:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at process.exit (internal/process/per_thread.js:167:15)
at Object.sendCrashResponse (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/logger.js:37:9)
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:271:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at processPromiseRejections (internal/process/promises.js:209:33)
at processTicksAndRejections (internal/process/task_queues.js:98:32) 

这是针对我创建的函数，该函数有时似乎执行，然后不执行。

exports.queueFunction = globalFunctions.runWith(runtimeOpts).https.onRequest((request, response) => {

try {
    challengeId = '';
    console.log("Running cron challenge...")
    var timesRun = 0;
    var interval = setInterval(() => {
        timesRun += 1;
        if (timesRun === 12) {
            console.log("Stopping cron challenge interval...")
            clearInterval(interval);
        }
        console.log("Executing challenge match...")
        getChallenges();
    }, 5000);
    response.status(200).send({ success: 'success' });
} catch (error) {
    response.status(500).send({ error: 'error' });
}

});

队列只是检查集合中是否存在匹配队列

db = admin.firestore();
const tourRef = db.collection('ChallengeQueue');
const snapshot = await tourRef.where('challengeId', '==', challengeId).get();
const queuedata = [];
if (snapshot.empty) {
    console.log('No users online.');
    return;
}
snapshot.forEach(doc => {
    if (doc.id !== playerId) {
        queuedata.push(doc.data());
    }
});

Answer 1

根据给出的错误信息，给定的queueFunction与它无关，因为它是queueMatch函数中的错误。

请提供globalFunctions 和runtimeOpts 对象。目前我只能假设globalFunctions被定义为import * as globalFunctions from "firebase-functions"。

关于为什么您的间隔有时会运行，这是因为您发出信号表明该函数已准备好在任何间隔回调运行之前终止（见下文）。一旦返回响应，“函数执行器”被认为可以安全关闭 - 在发送响应后您不应该发生任何重要的事情。

您的代码在功能上等同于：

exports.queueFunction = globalFunctions.runWith(runtimeOpts).https.onRequest((request, response) => {

  try {
      challengeId = '';
      console.log("Running cron challenge...")
      var timesRun = 0;
      var interval = 1 /* some number representing the ID of the interval */;
      response.status(200).send({ success: 'success' }); // response sent, terminate function
  } catch (error) {
      response.status(500).send({ error: 'error' }); // response sent, terminate function
  }

});

注意：在上面的代码块中，假设“终止函数”意味着立即调用process.exit()。实际上，“函数执行器”不会立即终止，但您的代码应该假定它是。