如何从 MS Access 文本字段中填充组合框，然后将组合框选择插入另一个表

Question

我正在尝试使用组合框中的信息插入 Access 表记录。我正在使用 winform 和 C#。我已经简化了我的项目，只包括问题区域。我展示了带有 4 个控件（2 个按钮和 2 个组合框）的三种方法。第一种方法是连接到 Access 数据库，然后在第一个组合框中显示表和视图的列表。此方法还将调用最后一个方法 SelectName( ) 并用所选数据库中预定表中的字段内容填充第二个组合框。第二种方法 (buttonInsert_Click()) 是我的问题所在。我希望该方法将所选项目从组合框 1 插入到所选表之一中单击插入按钮时来自组合框2。我可以插入到所选表中的唯一内容是

                     System.Data.DataRowView   

我的项目的 C# 部分如下。任何建议表示赞赏。谢谢。

    using System;
    using System.Collections.Generic;
    using System.ComponentModel;
    using System.Data;
    using System.Drawing;
    using System.Linq;
    using System.Text;
    using System.Windows.Forms;
    using System.Data.OleDb;

    namespace DbApp
    {
    public partial class Form1 : Form
    {
        private char ch = '"';
        private OleDbConnection dbConn;
        private string sql = "";


    public Form1()
    {
        InitializeComponent();
    }

    private void buttonConnect_Click(object sender, EventArgs e)
    {
        string connectionString = "";
        string stringData = "";

        openFileDialog1.Filter = "";
        openFileDialog1.ShowDialog();

        Text = openFileDialog1.FileName;
        stringData = openFileDialog1.FileName;

        connectionString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + ch + Text + ch;

        if (dbConn != null)
            dbConn.Close();

        dbConn = new OleDbConnection(connectionString);
        dbConn.Open();
        comboBox1.Items.Clear();
        DataTable info = dbConn.GetSchema("Tables");
        for (int x = 0; x < info.Rows.Count; ++x)
        {
            if ((info.Rows[x][3].ToString() == "TABLE") || (info.Rows[x][3].ToString() == "VIEW"))
            {
                comboBox1.Items.Add((object)info.Rows[x][2].ToString());
            }
        }

        SelectName();
    }

    private void buttonInsert_Click(object sender, EventArgs e)
    {
        string name = this.comboBox2.SelectedItem.ToString();

        try
        {
            dbConn = new OleDbConnection();
            dbConn.ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0; Data Source=" + ch + openFileDialog1.FileName + ch;
            dbConn.Open();

            sql = "INSERT INTO " + this.comboBox1.SelectedItem.ToString() + " (Names)" +
            "Values (@name)";
            OleDbCommand myCommand = new OleDbCommand(sql, dbConn);

            myCommand.Parameters.Add("@name", OleDbType.VarChar).Value = name;
            myCommand.ExecuteNonQuery();

            myCommand.Connection.Close();
        }
        catch (Exception err)
        {
            MessageBox.Show("Error: " + err.Message.ToString());
        }
    }

    private void SelectName()
    {
        string strCon = "Provider=Microsoft.ACE.OLEDB.12.0; Data Source=" + ch + openFileDialog1.FileName + ch;

        try
        {
            using (dbConn = new OleDbConnection(strCon))
            {
                dbConn.Open();
                sql = "SELECT Name FROM Names";
                OleDbDataAdapter adapter = new OleDbDataAdapter(new OleDbCommand(sql, dbConn));
                DataSet ds = new DataSet();
                adapter.Fill(ds, "Names");
                comboBox2.Items.Clear();
                this.comboBox2.DataSource = ds.Tables["Names"];
                this.comboBox2.DisplayMember = "Name";
            }
        }
        catch (Exception ex)
        {
            MessageBox.Show("Error: " + ex.Message.ToString());
        }
    }
}
}

Answer 1

试试这个：

string name = this.comboBox2.Text;