Firebase 函数在访问 Firestore 时崩溃

Question

您能在下面的代码中找到错误吗？

const functions = require("firebase-functions");
const admin = require("firebase-admin");
admin.initializeApp();



exports.GetShort = functions.https.onRequest((request, response) => {
    response.header("Access-Control-Allow-Origin", "*");
    longURL = request.query.long
    functions.logger.info("url is - " ,longURL)
    SaveToDB(longURL)
})


function SaveToDB(link){
    functions.logger.info("here")
    admin.firestore().collection("url").where("urlNames","array_contains",link).get().then(
  
        function(querySnapshot){
            functions.logger.info("snap, " ,querySnapshot)
            querySnapshot.forEach(function(doc) {
            functions.logger.info("things :  " ,doc.id, " => ", doc.data())

                // doc.data() is never undefined for query doc snapshots
                console.log(doc.id, " => ", doc.data());
            });
        }
    ) .catch(function(error) {
        functions.logger.info("Error getting documents: ", error);
    });
}

点击上述函数后，firebase-functions 日志会显示日志直到“这里”。之后它崩溃，没有更多的日志/堆栈跟踪。

下面是functions目录下packages.json的内容。

{
  "name": "functions",
  "description": "Cloud Functions for Firebase",
  "scripts": {
    "lint": "eslint .",
    "serve": "firebase emulators:start --only functions",
    "shell": "firebase functions:shell",
    "start": "npm run shell",
    "deploy": "firebase deploy --only functions",
    "logs": "firebase functions:log"
  },
  "engines": {
    "node": "14"
  },
  "main": "index.js",
  "dependencies": {
    "firebase-admin": "^9.8.0",
    "firebase-functions": "^3.14.1"
  },
  "devDependencies": {
    "eslint": "^7.6.0",
    "eslint-config-google": "^0.14.0",
    "firebase-functions-test": "^0.2.0"
  },
  "private": true
}

Answer 1

我建议您观看Firebase video series 中关于“JavaScript Promises”的 3 个视频，了解如何管理 Cloud Function 的生命周期以及处理对异步方法的调用。

特别是对于HTTPS Cloud Function，您需要以send()、redirect() 或end() 结束它。

所以你的代码可以修改如下：

exports.GetShort = functions.https.onRequest((request, response) => {
    response.header("Access-Control-Allow-Origin", "*");
    const longURL = request.query.long;
    functions.logger.info("url is - ", longURL)
    SaveToDB(longURL)
    .then(() => {
        response.status(200).send('Saved to DB');
    })
    .catch(error => {
        // See video series
        response.status(500).send(error);
    })
})


function SaveToDB(link) {
    functions.logger.info("here")
    return admin.firestore().collection("url").where("urlNames", "array_contains", link).get()
    .then(querySnapshot => {
        functions.logger.info("snap, ", querySnapshot)
        querySnapshot.forEach(function (doc) {
            functions.logger.info("things :  ", doc.id, " => ", doc.data())

            // doc.data() is never undefined for query doc snapshots
            console.log(doc.id, " => ", doc.data());
            
            // => Here, depending on your real functional requirements, you may need to use Promise.all()
            
        });
        return null;
    }
    ).catch(function (error) {
        functions.logger.info("Error getting documents: ", error);
        // Throw an error
    });
}

Answer 2

嗯，我发现了问题。有时愚蠢的事情会引起周围的大部分噪音。 我写的不是“array-contains”，而是“array_contains”。