【发布时间】:2017-08-15 04:12:53
【问题描述】:
我尝试通过 ajax 在 codeigniter 中使用数据表服务器端合并数据,但我得到错误结果,像这样
消息:在布尔值上调用成员函数 result()
文件名:models/model_masterdata_menu.php
行号: 66
private function _get_datatables_query()
{ //term is value of $_REQUEST['search']['value']
$column_search = array('m.menu_id, m.menu_nama, m.menu_url, sm.statusmenu_nama');
$column_order = array('m.menu_id, m.menu_nama, m.menu_url, sm.statusmenu_nama',NULL);
$order = array('m.menu_id' => 'desc');
$this->db->select('m.menu_id, m.menu_nama, m.mmenu_url, sm.statusmenu_nama');
$this->db->from('menu as m');
$this->db->join('status_menu sm', 'sm.statusmenu_id = m.statusmenu_id','left');
$i = 0;
foreach ($column_search as $item) // loop column
{
if($_POST['search']['value']) // if datatable send POST for search
{
if($i===0) // first loop
{
$this->db->group_start(); // open bracket. query Where with OR clause better with bracket. because maybe can combine with other WHERE with AND.
$this->db->like($item, $_POST['search']['value']);
}
else
{
$this->db->or_like($item, $_POST['search']['value']);
}
if(count($column_search) - 1 == $i) //last loop
$this->db->group_end(); //close bracke
}
$i++;
}
if(isset($_POST['order'])) // here order processing
{
$this->db->order_by($order[$_POST['order']['0']['column']], $_POST['order']['0']['dir']);
}
else if(isset($this->order))
{
/*$order = $this->order;*/
$this->db->order_by(key($order), $order[key($order)]);
}
}
function get_datatables()
{
$this->_get_datatables_query();
/*$this->_get_datatables_query();*/
if($_POST['length'] != -1)
$this->db->limit($_POST['length'], $_POST['start']);
$result = $query->result(); # added
}
怎么了? 谁能帮帮我?
【问题讨论】:
-
这是
foreach ($column_search as $item)第32行吗? -
@Jigar Shah,对不起,我稍后检查后收到错误调用数组上的成员函数 result()
-
只是一个顶部你的类和文件名应该只有第一个字母大写
Filename: models/Model_masterdata_menu.php而不是Filename: models/model_masterdata_menu.php这里解释codeigniter.com/user_guide/general/styleguide.html#file-naming -
@wolfgang1983,同样的错误没有变化
-
只是一个小费@muzamilindra
标签: php ajax codeigniter datatable