如何将单词保存为具有任意整数值的字典键？

Question

在对单词进行标记后，我试图弄清楚如何将它们保存为字典中的键并分配任意整数值。

尝试

import sys 
import re  
    
filename = sys.argv[1]
        
infile = open(filename, 'r')
    
for line in infile:    
    allwords = line.split()

    for word in allwords:
        word = word.rstrip('.:;!,"?)_')
        book = {word.lower()}   

print(book)

Answer 1

我不确定我是否理解问题的逻辑，所以我提供了另外 2 个选项：

随机导入 表单集合导入计数器

words_test = ['hello', 'world', 'goodbye', 'tomorrow','jack','jack']

选项 1 - Christopher Peisert

book = {word: random.randint(0, 1000) for word in words_test}

选项 2 - 使用集合 - 将删除重复项

words_set = set(words_test)

选项 3 - 使用计数器。见

# https://docs.python.org/3.8/library/collections.html#collections.Counter

counter = Counter(words_test)

Answer 2

book = {word.lower()}

这是创建一组单项，而不是字典。

在循环之前创建字典。然后使用符号dict_name[key]=value 设置值来设置键值对：

import sys 
import re
import random

filename = sys.argv[1]
    
infile = open(filename, 'r')

book = {}

for line in infile:
    allwords = line.split()

    for word in allwords:
        word = word.rstrip('.:;!,"?)_')
        book[word.lower()] = random.randint(0,1000)

print(book)

Answer 3

随机值的字典理解

一种解决方案是使用字典推导并分配随机整数值。

import random

words_test = ['hello', 'world', 'goodbye', 'tomorrow']
book = {word: random.randint(0, 1000) for word in words_test}

print(book)

输出

{'hello': 318, 'world': 576, 'goodbye': 699, 'tomorrow': 847}

使用dict.fromkeys() 的相同整数值

如果整数值不需要是随机的，你也可以使用：

words_test = ['hello', 'world', 'goodbye', 'tomorrow']
book = dict.fromkeys(words_test, 1)

print(book)

输出

{'hello': 1, 'world': 1, 'goodbye': 1, 'tomorrow': 1}

每次迭代添加一个键值对的循环

words_test = ['hello', 'world', 'goodbye', 'tomorrow']

book = dict()
for word in words_test:
    book[word] = 1

print(book)

输出

{'hello': 1, 'world': 1, 'goodbye': 1, 'tomorrow': 1}