您最喜欢的非内置 LINQ to Objects 运算符是什么？ [关闭]

Question

通过扩展方法，我们可以编写方便的 LINQ 运算符来解决一般问题。

我想了解您在 System.Linq 命名空间中缺少哪些方法或重载，以及您是如何实现它们的。

简洁优雅的实现，可能使用现有的方法，是首选。

Answer 1

追加和前置

（自编写此答案以来，这些已添加到 .NET。）

/// <summary>Adds a single element to the end of an IEnumerable.</summary>
/// <typeparam name="T">Type of enumerable to return.</typeparam>
/// <returns>IEnumerable containing all the input elements, followed by the
/// specified additional element.</returns>
public static IEnumerable<T> Append<T>(this IEnumerable<T> source, T element)
{
    if (source == null)
        throw new ArgumentNullException("source");
    return concatIterator(element, source, false);
}

/// <summary>Adds a single element to the start of an IEnumerable.</summary>
/// <typeparam name="T">Type of enumerable to return.</typeparam>
/// <returns>IEnumerable containing the specified additional element, followed by
/// all the input elements.</returns>
public static IEnumerable<T> Prepend<T>(this IEnumerable<T> tail, T head)
{
    if (tail == null)
        throw new ArgumentNullException("tail");
    return concatIterator(head, tail, true);
}

private static IEnumerable<T> concatIterator<T>(T extraElement,
    IEnumerable<T> source, bool insertAtStart)
{
    if (insertAtStart)
        yield return extraElement;
    foreach (var e in source)
        yield return e;
    if (!insertAtStart)
        yield return extraElement;
}

Answer 2

我很惊讶还没有人提到MoreLINQ project。它由Jon Skeet 发起，并在此过程中获得了一些开发人员。从项目页面：

LINQ to Objects 缺少一些 理想的功能。

该项目将增强 LINQ 以 具有额外方法的对象，在 保持精神的方式 LINQ。

查看Operators Overview wiki 页面以获取已实现的运算符列表。

这当然是从一些干净优雅的源代码中学习的好方法。

Answer 3

每个

对于纯粹主义者来说没什么，但它很有用！

 public static void Each<T>(this IEnumerable<T> items, Action<T> action)
 {
   foreach (var i in items)
      action(i);
 }

Answer 4

ToQueue 和 ToStack

/// <summary>Creates a <see cref="Queue&lt;T&gt;"/> from an enumerable
/// collection.</summary>
public static Queue<T> ToQueue<T>(this IEnumerable<T> source)
{
    if (source == null)
        throw new ArgumentNullException("source");
    return new Queue<T>(source);
}

/// <summary>Creates a <see cref="Stack&lt;T&gt;"/> from an enumerable
/// collection.</summary>
public static Stack<T> ToStack<T>(this IEnumerable<T> source)
{
    if (source == null)
        throw new ArgumentNullException("source");
    return new Stack<T>(source);
}

Answer 5

IsEmpty

​​>

public static bool IsEmpty<T>(this IEnumerable<T> source)
{
    return !source.Any();
}

Answer 6

在和不在

其他两个众所周知的 SQL 构造的 C# 等效项

/// <summary>
/// Determines if the source value is contained in the list of possible values.
/// </summary>
/// <typeparam name="T">The type of the objects</typeparam>
/// <param name="value">The source value</param>
/// <param name="values">The list of possible values</param>
/// <returns>
///     <c>true</c> if the source value matches at least one of the possible values; otherwise, <c>false</c>.
/// </returns>
public static bool In<T>(this T value, params T[] values)
{
    if (values == null)
        return false;

    if (values.Contains<T>(value))
        return true;

    return false;
}

/// <summary>
/// Determines if the source value is contained in the list of possible values.
/// </summary>
/// <typeparam name="T">The type of the objects</typeparam>
/// <param name="value">The source value</param>
/// <param name="values">The list of possible values</param>
/// <returns>
///     <c>true</c> if the source value matches at least one of the possible values; otherwise, <c>false</c>.
/// </returns>
public static bool In<T>(this T value, IEnumerable<T> values)
{
    if (values == null)
        return false;

    if (values.Contains<T>(value))
        return true;

    return false;
}

/// <summary>
/// Determines if the source value is not contained in the list of possible values.
/// </summary>
/// <typeparam name="T">The type of the objects</typeparam>
/// <param name="value">The source value</param>
/// <param name="values">The list of possible values</param>
/// <returns>
///     <c>false</c> if the source value matches at least one of the possible values; otherwise, <c>true</c>.
/// </returns>
public static bool NotIn<T>(this T value, params T[] values)
{
    return In(value, values) == false;
}

/// <summary>
/// Determines if the source value is not contained in the list of possible values.
/// </summary>
/// <typeparam name="T">The type of the objects</typeparam>
/// <param name="value">The source value</param>
/// <param name="values">The list of possible values</param>
/// <returns>
///     <c>false</c> if the source value matches at least one of the possible values; otherwise, <c>true</c>.
/// </returns>
public static bool NotIn<T>(this T value, IEnumerable<T> values)
{
    return In(value, values) == false;
}

Answer 7

AsIEnumerable

/// <summary>
/// Returns a sequence containing one element.
/// </summary>
public static IEnumerable<T> AsIEnumerable<T>(this T obj)
{
    yield return obj;
}  

用法：

var nums = new[] {12, 20, 6};
var numsWith5Prepended = 5.AsIEnumerable().Concat(nums);   

Answer 8

连接字符串

与string.Join基本相同，但是：

• 能够在任何集合上使用它，而不仅仅是字符串集合（在每个元素上调用 ToString）

• 能够为每个字符串添加前缀和后缀。

• 作为扩展方法。我觉得 string.Join 很烦人，因为它是静态的，这意味着在一系列操作中，它的词法顺序不正确。

---

/// <summary>
/// Turns all elements in the enumerable to strings and joins them using the
/// specified string as the separator and the specified prefix and suffix for
/// each string.
/// <example>
///   <code>
///     var a = (new[] { "Paris", "London", "Tokyo" }).JoinString(", ", "[", "]");
///     // a contains "[Paris], [London], [Tokyo]"
///   </code>
/// </example>
/// </summary>
public static string JoinString<T>(this IEnumerable<T> values,
    string separator = null, string prefix = null, string suffix = null)
{
    if (values == null)
        throw new ArgumentNullException("values");

    using (var enumerator = values.GetEnumerator())
    {
        if (!enumerator.MoveNext())
            return "";
        StringBuilder sb = new StringBuilder();
        sb.Append(prefix).Append(enumerator.Current.ToString()).Append(suffix);
        while (enumerator.MoveNext())
            sb.Append(separator).Append(prefix)
              .Append(enumerator.Current.ToString()).Append(suffix);
        return sb.ToString();
    }
}

Answer 9

订单

/// <summary>Sorts the elements of a sequence in ascending order.</summary>
public static IEnumerable<T> Order<T>(this IEnumerable<T> source)
{
    return source.OrderBy(x => x);
}

Answer 10

随机播放

public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> items)
{
    var random = new Random();
    return items.OrderBy(x => random.Next());
}

编辑：上面的实现似乎有几个问题。这是基于@LukeH 的代码和来自@ck 和@Strilanc 的cmets 的改进版本。

private static Random _rand = new Random();
public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> source)
{
    var items = source == null ? new T[] { } : source.ToArray();
    var count = items.Length;
    while(count > 0)
    {
        int toReturn = _rand.Next(0, count);
        yield return items[toReturn];
        items[toReturn] = items[count - 1];
        count--;
    }
}

Answer 11

循环

这是我刚想到的一个很酷的。 （如果我只是想到它，也许它没那么有用？但我想到它是因为我有它的用处。）重复循环一个序列以生成一个无限序列。这完成了类似于Enumerable.Range 和Enumerable.Repeat 给你的东西，除了它可以用于任意（不像Range）序列（不像@987654324 @):

public static IEnumerable<T> Loop<T>(this IEnumerable<T> source)
{
    while (true)
    {
        foreach (T item in source)
        {
            yield return item;
        }
    }
}

用法：

var numbers = new[] { 1, 2, 3 };
var looped = numbers.Loop();

foreach (int x in looped.Take(10))
{
    Console.WriteLine(x);
}

输出：

1 2 3 1 2 3 1 2 3 1

注意：我想您也可以通过以下方式完成此操作：

var looped = Enumerable.Repeat(numbers, int.MaxValue).SelectMany(seq => seq);

...但我认为Loop 更清晰。

Answer 12

最小元素

Min 只返回指定表达式返回的最小值，而不是给出这个最小值元素的原始元素。

/// <summary>Returns the first element from the input sequence for which the
/// value selector returns the smallest value.</summary>
public static T MinElement<T, TValue>(this IEnumerable<T> source,
        Func<T, TValue> valueSelector) where TValue : IComparable<TValue>
{
    if (source == null)
        throw new ArgumentNullException("source");
    if (valueSelector == null)
        throw new ArgumentNullException("valueSelector");
    using (var enumerator = source.GetEnumerator())
    {
        if (!enumerator.MoveNext())
            throw new InvalidOperationException("source contains no elements.");
        T minElem = enumerator.Current;
        TValue minValue = valueSelector(minElem);
        while (enumerator.MoveNext())
        {
            TValue value = valueSelector(enumerator.Current);
            if (value.CompareTo(minValue) < 0)
            {
                minValue = value;
                minElem = enumerator.Current;
            }
        }
        return minElem;
    }
}

Answer 13

索引

/// <summary>
/// Returns the index of the first element in this <paramref name="source"/>
/// satisfying the specified <paramref name="condition"/>. If no such elements
/// are found, returns -1.
/// </summary>
public static int IndexOf<T>(this IEnumerable<T> source, Func<T, bool> condition)
{
    if (source == null)
        throw new ArgumentNullException("source");
    if (condition == null)
        throw new ArgumentNullException("condition");
    int index = 0;
    foreach (var v in source)
    {
        if (condition(v))
            return index;
        index++;
    }
    return -1;
}

Answer 14

块

返回特定大小的块。 x.Chunks(2) of 1,2,3,4,5 将返回两个数组，分别是 1,2 和 3,4。 x.Chunks(2,true) 将返回 1,2、3,4 和 5。

public static IEnumerable<T[]> Chunks<T>(this IEnumerable<T> xs, int size, bool returnRest = false)
{
    var curr = new T[size];

    int i = 0;

    foreach (var x in xs)
    {
        if (i == size)
        {
            yield return curr;
            i = 0;
            curr = new T[size];
        }

        curr[i++] = x;
    }

    if (returnRest)
        yield return curr.Take(i).ToArray();
}

Answer 15

ToHashSet

public static HashSet<T> ToHashSet<T>(this IEnumerable<T> items)
{
    return new HashSet<T>(items);
}

Answer 16

FirstOrDefault 指定了默认值

/// <summary>
/// Returns the first element of a sequence, or a default value if the
/// sequence contains no elements.
/// </summary>
/// <typeparam name="T">The type of the elements of
/// <paramref name="source"/>.</typeparam>
/// <param name="source">The <see cref="IEnumerable&lt;T&gt;"/> to return
/// the first element of.</param>
/// <param name="default">The default value to return if the sequence contains
/// no elements.</param>
/// <returns><paramref name="default"/> if <paramref name="source"/> is empty;
/// otherwise, the first element in <paramref name="source"/>.</returns>
public static T FirstOrDefault<T>(this IEnumerable<T> source, T @default)
{
    if (source == null)
        throw new ArgumentNullException("source");
    using (var e = source.GetEnumerator())
    {
        if (!e.MoveNext())
            return @default;
        return e.Current;
    }
}

/// <summary>
/// Returns the first element of a sequence, or a default value if the sequence
/// contains no elements.
/// </summary>
/// <typeparam name="T">The type of the elements of
/// <paramref name="source"/>.</typeparam>
/// <param name="source">The <see cref="IEnumerable&lt;T&gt;"/> to return
/// the first element of.</param>
/// <param name="predicate">A function to test each element for a
/// condition.</param>
/// <param name="default">The default value to return if the sequence contains
/// no elements.</param>
/// <returns><paramref name="default"/> if <paramref name="source"/> is empty
/// or if no element passes the test specified by <paramref name="predicate"/>;
/// otherwise, the first element in <paramref name="source"/> that passes
/// the test specified by <paramref name="predicate"/>.</returns>
public static T FirstOrDefault<T>(this IEnumerable<T> source,
    Func<T, bool> predicate, T @default)
{
    if (source == null)
        throw new ArgumentNullException("source");
    if (predicate == null)
        throw new ArgumentNullException("predicate");
    using (var e = source.GetEnumerator())
    {
        while (true)
        {
            if (!e.MoveNext())
                return @default;
            if (predicate(e.Current))
                return e.Current;
        }
    }
}

Answer 17

插入之间

在每对连续元素之间插入一个元素。

/// <summary>Inserts the specified item in between each element in the input
/// collection.</summary>
/// <param name="source">The input collection.</param>
/// <param name="extraElement">The element to insert between each consecutive
/// pair of elements in the input collection.</param>
/// <returns>A collection containing the original collection with the extra
/// element inserted. For example, new[] { 1, 2, 3 }.InsertBetween(0) returns
/// { 1, 0, 2, 0, 3 }.</returns>
public static IEnumerable<T> InsertBetween<T>(
    this IEnumerable<T> source, T extraElement)
{
    return source.SelectMany(val => new[] { extraElement, val }).Skip(1);
}

Answer 18

EmptyIfNull

这是一个有争议的问题；我相信很多纯粹主义者会反对null成功的“实例方法”。

/// <summary>
/// Returns an IEnumerable<T> as is, or an empty IEnumerable<T> if it is null
/// </summary>
public static IEnumerable<T> EmptyIfNull<T>(this IEnumerable<T> source)
{
    return source ?? Enumerable.Empty<T>();
}    

用法：

foreach(var item in myEnumerable.EmptyIfNull())
{
  Console.WriteLine(item);   
}

Answer 19

解析

这涉及到一个自定义委托（可以使用IParser<T> 接口，但我选择了一个委托，因为它更简单），用于将字符串序列解析为值序列，跳过解析失败的元素。

public delegate bool TryParser<T>(string text, out T value);

public static IEnumerable<T> Parse<T>(this IEnumerable<string> source,
                                      TryParser<T> parser)
{
    source.ThrowIfNull("source");
    parser.ThrowIfNull("parser");

    foreach (string str in source)
    {
        T value;
        if (parser(str, out value))
        {
            yield return value;
        }
    }
}

用法：

var strings = new[] { "1", "2", "H3llo", "4", "five", "6", "se7en" };
var numbers = strings.Parse<int>(int.TryParse);

foreach (int x in numbers)
{
    Console.WriteLine(x);
}

输出：

1 2 4 6

这个名字很难命名。我不确定Parse 是否是最好的选择（至少它很简单），或者像ParseWhereValid 这样的东西是否会更好。

Answer 20

压缩合并

这是我的Zip 版本，它的工作原理就像一个真正的拉链。它不会将两个值合二为一，而是返回一个组合的 IEnumerable。重载、跳过右尾和/或左尾是可能的。

public static IEnumerable<TSource> ZipMerge<TSource>(
        this IEnumerable<TSource> first,
        IEnumerable<TSource> second)
{
    using (var secondEnumerator = second.GetEnumerator())
    {
        foreach (var item in first)
        {
            yield return item;

            if (secondEnumerator.MoveNext())
                yield return secondEnumerator.Current;
        }

        while (secondEnumerator.MoveNext())
            yield return secondEnumerator.Current;
    }
}

Answer 21

随机样本

如果您有一个中等规模的数据集（例如，超过 100 个项目）并且您只想查看其中的随机样本，这里有一个简单的函数非常有用。

public static IEnumerable<T> RandomSample<T>(this IEnumerable<T> source,
                                             double percentage)
{
    source.ThrowIfNull("source");

    var r = new Random();
    return source.Where(x => (r.NextDouble() * 100.0) < percentage);
}

用法：

List<DataPoint> data = GetData();

// Sample roughly 3% of the data
var sample = data.RandomSample(3.0);

// Verify results were correct for this sample
foreach (DataPoint point in sample)
{
    Console.WriteLine("{0} => {1}", point, DoCalculation(point));
}

注意事项：

1. 不太适合小集合，因为返回的项目数量是概率性的（在小序列上很容易返回零）。
2. 不太适合大型集合或数据库查询，因为它涉及枚举序列中的每个项目。

Answer 22

断言计数

有效地确定 IEnumerable<T> 是否包含至少/恰好/最多一定数量的元素。

public enum CountAssertion
{
    AtLeast,
    Exact,
    AtMost
}

/// <summary>
/// Asserts that the number of items in a sequence matching a specified predicate satisfies a specified CountAssertion.
/// </summary>
public static bool AssertCount<T>(this IEnumerable<T> source, int countToAssert, CountAssertion assertion, Func<T, bool> predicate)
{
    if (source == null)
        throw new ArgumentNullException("source");

    if (predicate == null)
        throw new ArgumentNullException("predicate");

    return source.Where(predicate).AssertCount(countToAssert, assertion);
}

/// <summary>
/// Asserts that the number of elements in a sequence satisfies a specified CountAssertion.
/// </summary>
public static bool AssertCount<T>(this IEnumerable<T> source, int countToAssert, CountAssertion assertion)
{
    if (source == null)
        throw new ArgumentNullException("source");

    if (countToAssert < 0)
        throw new ArgumentOutOfRangeException("countToAssert");    

    switch (assertion)
    {
        case CountAssertion.AtLeast:
            return AssertCountAtLeast(source, GetFastCount(source), countToAssert);

        case CountAssertion.Exact:
            return AssertCountExact(source, GetFastCount(source), countToAssert);

        case CountAssertion.AtMost:
            return AssertCountAtMost(source, GetFastCount(source), countToAssert);

        default:
            throw new ArgumentException("Unknown CountAssertion.", "assertion");
    }

}

private static int? GetFastCount<T>(IEnumerable<T> source)
{
    var genericCollection = source as ICollection<T>;
    if (genericCollection != null)
        return genericCollection.Count;

    var collection = source as ICollection;
    if (collection != null)
        return collection.Count;

    return null;
}

private static bool AssertCountAtMost<T>(IEnumerable<T> source, int? fastCount, int countToAssert)
{
    if (fastCount.HasValue)
        return fastCount.Value <= countToAssert;

    int countSoFar = 0;

    foreach (var item in source)
    {
        if (++countSoFar > countToAssert) return false;
    }

    return true;
}

private static bool AssertCountExact<T>(IEnumerable<T> source, int? fastCount, int countToAssert)
{
    if (fastCount.HasValue)
        return fastCount.Value == countToAssert;

    int countSoFar = 0;

    foreach (var item in source)
    {
        if (++countSoFar > countToAssert) return false;
    }

    return countSoFar == countToAssert;
}

private static bool AssertCountAtLeast<T>(IEnumerable<T> source, int? fastCount, int countToAssert)
{
    if (countToAssert == 0)
        return true;

    if (fastCount.HasValue)
        return fastCount.Value >= countToAssert;

    int countSoFar = 0;

    foreach (var item in source)
    {
        if (++countSoFar >= countToAssert) return true;
    }

    return false;
}

用法：

var nums = new[] { 45, -4, 35, -12, 46, -98, 11 };
bool hasAtLeast3Positive = nums.AssertCount(3, CountAssertion.AtLeast, i => i > 0); //true
bool hasAtMost1Negative = nums.AssertCount(1, CountAssertion.AtMost, i => i < 0); //false
bool hasExactly2Negative = nums.AssertCount(2, CountAssertion.Exact, i => i < 0); //false

Answer 23

窗口

枚举长度为size 包含最新值的数组（“windows”）。
{ 0, 1, 2, 3 } 变为{ [0, 1], [1, 2], [2, 3] }。

例如，我正在使用它通过连接两个点来绘制折线图。

public static IEnumerable<TSource[]> Window<TSource>(
    this IEnumerable<TSource> source)
{
    return source.Window(2);
}

public static IEnumerable<TSource[]> Window<TSource>(
    this IEnumerable<TSource> source, int size)
{
    if (size <= 0)
        throw new ArgumentOutOfRangeException("size");

    return source.Skip(size).WindowHelper(size, source.Take(size));
}

private static IEnumerable<TSource[]> WindowHelper<TSource>(
    this IEnumerable<TSource> source, int size, IEnumerable<TSource> init)
{
    Queue<TSource> q = new Queue<TSource>(init);

    yield return q.ToArray();

    foreach (var value in source)
    {
        q.Dequeue();
        q.Enqueue(value);
        yield return q.ToArray();
    }
}

Answer 24

一个、两个、MoreThanOne、AtLeast、AnyAtAll

public static bool One<T>(this IEnumerable<T> enumerable)
{
    using (var enumerator = enumerable.GetEnumerator())
        return enumerator.MoveNext() && !enumerator.MoveNext();
}

public static bool Two<T>(this IEnumerable<T> enumerable)
{
    using (var enumerator = enumerable.GetEnumerator())
        return enumerator.MoveNext() && enumerator.MoveNext() && !enumerator.MoveNext();
}

public static bool MoreThanOne<T>(this IEnumerable<T> enumerable)
{
    return enumerable.Skip(1).Any();
}

public static bool AtLeast<T>(this IEnumerable<T> enumerable, int count)
{
    using (var enumerator = enumerable.GetEnumerator())
        for (var i = 0; i < count; i++)
            if (!enumerator.MoveNext())
                return false;
    return true;
}

public static bool AnyAtAll<T>(this IEnumerable<T> enumerable)
{
    return enumerable != null && enumerable.Any();
}

Answer 25

SkipLast 和 TakeLast

/// <summary>
/// Enumerates the items of this collection, skipping the last
/// <paramref name="count"/> items. Note that the memory usage of this method
/// is proportional to <paramref name="count"/>, but the source collection is
/// only enumerated once, and in a lazy fashion. Also, enumerating the first
/// item will take longer than enumerating subsequent items.
/// </summary>
public static IEnumerable<T> SkipLast<T>(this IEnumerable<T> source, int count)
{
    if (source == null)
        throw new ArgumentNullException("source");
    if (count < 0)
        throw new ArgumentOutOfRangeException("count",
            "count cannot be negative.");
    if (count == 0)
        return source;
    return skipLastIterator(source, count);
}
private static IEnumerable<T> skipLastIterator<T>(IEnumerable<T> source,
    int count)
{
    var queue = new T[count];
    int headtail = 0; // tail while we're still collecting, both head & tail
                      // afterwards because the queue becomes completely full
    int collected = 0;

    foreach (var item in source)
    {
        if (collected < count)
        {
            queue[headtail] = item;
            headtail++;
            collected++;
        }
        else
        {
            if (headtail == count) headtail = 0;
            yield return queue[headtail];
            queue[headtail] = item;
            headtail++;
        }
    }
}

/// <summary>
/// Returns a collection containing only the last <paramref name="count"/>
/// items of the input collection. This method enumerates the entire
/// collection to the end once before returning. Note also that the memory
/// usage of this method is proportional to <paramref name="count"/>.
/// </summary>
public static IEnumerable<T> TakeLast<T>(this IEnumerable<T> source, int count)
{
    if (source == null)
        throw new ArgumentNullException("source");
    if (count < 0)
        throw new ArgumentOutOfRangeException("count",
            "count cannot be negative.");
    if (count == 0)
        return new T[0];

    var queue = new Queue<T>(count + 1);
    foreach (var item in source)
    {
        if (queue.Count == count)
            queue.Dequeue();
        queue.Enqueue(item);
    }
    return queue.AsEnumerable();
}

Answer 26

重复

与 Ani 的 AssertCount 方法（我使用一种称为 CountAtLeast 的方法）结合使用，可以很容易地在一个序列中找到多次出现的元素：

public static IEnumerable<T> Duplicates<T, TKey>(this IEnumerable<T> source,
    Func<T, TKey> keySelector = null, IEqualityComparer<TKey> comparer = null)
{
    source.ThrowIfNull("source");
    keySelector = keySelector ?? new Func<T, TKey>(x => x);
    comparer = comparer ?? EqualityComparer<TKey>.Default;

    return source.GroupBy(keySelector, comparer)
        .Where(g => g.CountAtLeast(2))
        .SelectMany(g => g);
}

Answer 27

如果

IEnumerable 和 IQueryable 上的可选 Where 子句。在为查询构建谓词和 lambda 时避免使用 if 语句。当您在编译时不知道是否应该应用过滤器时很有用。

public static IEnumerable<TSource> WhereIf<TSource>(
            this IEnumerable<TSource> source, bool condition,
            Func<TSource, bool> predicate)
{
    return condition ? source.Where(predicate) : source;
}

用途：

var custs = Customers.WhereIf(someBool, x=>x.EyeColor=="Green");

LINQ WhereIf At ExtensionMethod.NET 借用自Andrew's blog。

Answer 28

具有初始容量的 ToList 和 ToDictionary

ToList 和 ToDictionary 重载暴露了基础集合类的初始容量。当源长度已知或有界时偶尔有用。

public static List<TSource> ToList<TSource>(
    this IEnumerable<TSource> source, 
    int capacity)
{
    if (source == null)
    {
        throw new ArgumentNullException("source");
    }
    var list = new List<TSource>(capacity);
    list.AddRange(source);
    return list;
}     

public static Dictionary<TKey, TSource> ToDictionary<TSource, TKey>(
    this IEnumerable<TSource> source, 
    Func<TSource, TKey> keySelector, 
    int capacity,
    IEqualityComparer<TKey> comparer = null)
{
    return source.ToDictionary<TSource, TKey, TSource>(
                  keySelector, x => x, capacity, comparer);
}

public static Dictionary<TKey, TElement> ToDictionary<TSource, TKey, TElement>(
    this IEnumerable<TSource> source, 
    Func<TSource, TKey> keySelector, 
    Func<TSource, TElement> elementSelector,
    int capacity,
    IEqualityComparer<TKey> comparer = null)
{
    if (source == null)
    {
        throw new ArgumentNullException("source");
    }
    if (keySelector == null)
    {
        throw new ArgumentNullException("keySelector");
    }
    if (elementSelector == null)
    {
        throw new ArgumentNullException("elementSelector");
    }
    var dictionary = new Dictionary<TKey, TElement>(capacity, comparer);
    foreach (TSource local in source)
    {
        dictionary.Add(keySelector(local), elementSelector(local));
    }
    return dictionary;
}

Answer 29

CountUpTo

static int CountUpTo<T>(this IEnumerable<T> source, int maxCount)
{
    if (maxCount == 0)
        return 0;

    var genericCollection = source as ICollection<T>; 
    if (genericCollection != null) 
        return Math.Min(maxCount, genericCollection.Count);

    var collection = source as ICollection; 
    if (collection != null)
        return Math.Min(maxCount, collection.Count);

    int count = 0;
    foreach (T item in source)
        if (++count >= maxCount)
            break;
    return count;
}

Answer 30

合并

public static T Coalesce<T>(this IEnumerable<T> items) {
   return items.Where(x => x != null && !x.Equals(default(T))).FirstOrDefault();
   // return items.OfType<T>().FirstOrDefault(); // Gabe's take
}