如何从 Body android c# 将数据发布到 rest api JSON答案

【问题标题】：how to post data to rest api JSON from Body android c#如何从 Body android c# 将数据发布到 rest api JSON
【发布时间】：2020-10-03 12:07:09
【问题描述】：

谁能帮我找出解决办法？我需要使用 POST 方法注册数据，从 Body 发送参数。我正在使用此代码

  public static async Task<HttpResponseMessage> Signup(Register register)
    {
        HttpResponseMessage result=null;
        try
        {
            string url = Constant.url + "api/services/app/Account/Register";
            HttpClient _client = new HttpClient();
            var content = JsonConvert.SerializeObject(register);
            result = await _client.PostAsync(url, new StringContent(content, Encoding.UTF32, "application/json"));
        }
        catch(Exception ex)
        {
        }
            return result;
    }

但我收到 500 内部服务器错误。请帮助我。

【问题讨论】：

检查您的 api 代码和 api 错误日志以获取更多信息
在不知道您向服务器发送什么以及服务器期望什么的情况下，没有人可以帮助您解决问题。 500 也表示服务器有问题。所以你必须检查和服务器的代码，看看有什么问题

标签： android android-studio xamarin.android http-post webapi

【解决方案1】：

  public static  Signup_Root Check_xsignup(Register register)
    {
        HttpResponseMessage result = null;
        string resultt = "";
        Signup_Root lp =null;
        try
        {
            string jObj = JsonConvert.SerializeObject(register);
            StringContent content = new StringContent(jObj, System.Text.Encoding.UTF8);
            MediaTypeHeaderValue mValue = new MediaTypeHeaderValue("application/json");
            content.Headers.ContentType = mValue;
            string url = Constant.url + "api/services/app/Account/Register";
            HttpClient _client = new HttpClient();
            result =  _client.PostAsync(url, content).Result;
            if (result.StatusCode == HttpStatusCode.OK)
            {
                resultt = result.Content.ReadAsStringAsync().Result;
                lp = JsonConvert.DeserializeObject<Signup_Root>(resultt);
            }
        }
        catch (Java.Lang.Exception ex)
        {

        }
        return lp;
    }

试试这个，它会工作的

【讨论】：

【解决方案2】：

你可以这样使用它：

public class MakeRequest extends AsyncTask<String, Void, JSONObject> {

        protected void onPreExecute(){ }

        protected JSONObject doInBackground(String... arg0) {

            try {
                URL url = new URL(AppConstants.DEMO_API); // here is your URL path
                //params....
                JSONObject postDataParams = new JSONObject();
                JSONObject jsonObject = new JSONObject();
                jsonObject.put("type","claim");
                postDataParams.put("data", jsonObject);
                Log.e(TAG, postDataParams.toString());
                postDataParams.put("ctx","j");
                postDataParams.put("email", "abc@gmail.com");

                HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                conn.setReadTimeout(60000 /* milliseconds */);
                conn.setConnectTimeout(60000 /* milliseconds */);
                conn.setRequestMethod("POST"/* meathod */);
                conn.setDoInput(true);
                conn.setDoOutput(true);

                OutputStream os = conn.getOutputStream();
                BufferedWriter writer = new BufferedWriter(
                        new OutputStreamWriter(os, "UTF-8"));
                writer.write(getPostDataString(postDataParams));

                writer.flush();
                writer.close();
                os.close();

                //response....
                int responseCode=conn.getResponseCode();

                if (responseCode == HttpsURLConnection.HTTP_OK){

                    BufferedReader in=new BufferedReader(new
                            InputStreamReader(
                            conn.getInputStream()));

                    StringBuffer sb = new StringBuffer("");
                    String line="";

                    while((line = in.readLine()) != null) {
                        sb.append(line);
                        break;
                    }
                    in.close();

                    // getting JSON string from URL
                    JSONObject json = new JSONObject(sb.toString());
                    return json;
                }
                else {
                    return new JSONObject();
                }
            }
            catch(Exception e){
                e.printStackTrace();

                return new JSONObject();
            }

        }

        @Override
        protected void onPostExecute(JSONObject jsonObject) {
            super.onPostExecute(jsonObject);
            
        }
    }

【讨论】：