使用 async/await 时，如何在调用出错时停止执行函数？

Question

假设我们有这样一个函数：

Router.get('/', async function (req, res, next) {
  let result = await someFunction().catch(next)
  someOtherCall()
})

如果出错，它会通过调用next(error_reason) 继续处理全局错误处理程序。但是，如果someFunction() 失败，我们根本不希望someOtherCall() 运行。目前，我可以看到两种解决方法：

// Suggestion from https://stackoverflow.com/q/28835780/3832377
Router.get('/', async function (req, res, next) {
  let result = await someFunction().catch(next)
  if (!result) return // Ugly, especially if we have to run it after every call.
  someOtherCall()
})

Router.get('/', async function (req, res, next) {
  let result = someFunction().then(() => {
    // Much less work, but gets us back to using callbacks, which async/await were
    // meant to help fix for us.
    someOtherCall()
  }).catch(next)
})

如果任何函数调用并不意味着在每个函数调用后添加另一个语句或使用回调，是否有更简单的方法来阻止函数执行？

Answer 1

你可以简单地使用try-catch:

Router.get('/', async function (req, res, next) {
  try { 
    let result = await someFunction()
    someOtherCall()
  }
  catch(exception) {
    next(exception)
  }
})