【发布时间】:2018-06-12 04:37:14
【问题描述】:
arr1 = ['a', 'b', 'c'] ;
arr2 = ['1', '2', '3', '4'];
我解释
// run time
query() {
stuff1 = a;
stuff2 = 1;
}
query() {
stuff1 = a;
stuff2 = 2;
}
query() {
stuff1 = a;
stuff2 = 3;
}
query() {
stuff1 = a;
stuff2 = 4;
}
query() {
stuff1 = b;
stuff2 = 1;
}
query() {
stuff1 = b;
stuff2 = 2;
}
query() {
stuff1 = b;
stuff2 = 3;
}
query() {
stuff1 = b;
stuff2 = 4;
}
...
query() {
stuff1 = c;
stuff2 = 6;
}
如何编写代码?
_.map(arr1, (res) => { reutrn _.map(arr2, (res2, res1) => ... } blabla
我没有想法...
如果我使用 zipWith,a:1 b:2 c:3 ... 但我不想要它
谢谢
【问题讨论】:
标签: javascript vue.js lodash feathersjs