【问题标题】:Find if any array entry matches an object property查找是否有任何数组条目与对象属性匹配
【发布时间】:2016-10-28 12:10:35
【问题描述】:

我有一个数组:

 arr=[
      "EMPRESA",
      "CD_DIRECAO",
      "DT_INI_DIRECAO"
    ]

我有一个对象:

primary = {
           "EMPRESA": {"type": "varchar"},
           "CD_DIRECAO": {"type": "varchar"},
           "DT_INI_DIRECAO": {"type": "date"},
           "CD_DEPT": {"type": "varchar"},
           "DT_INI_DEPT": {"type": "date"},
           "ANO": {"type": "number"},
           "MES": {"type": "number"},
           "TP_CUSTO": {"type": "varchar"},
          }

我需要检查主目录中是否存在至少一个 arr 元素。 感谢您的帮助。

【问题讨论】:

  • lodash: _.intersection(arr, _.keys(primary)).length

标签: javascript arrays object lodash


【解决方案1】:

您可以使用Array#some 进行迭代并检查密钥是否存在。

var arr = ["EMPRESA", "CD_DIRECAO", "DT_INI_DIRECAO"],
    primary = { EMPRESA: { type: "varchar"}, CD_DIRECAO: { type: "varchar"}, DT_INI_DIRECAO: { type: "date"}, CD_DEPT: { type : "varchar"}, DT_INI_DEPT: { type: "date"}, ANO: { type: "number"},  MES: { type: "number"}, TP_CUSTO: { type: "varchar"}},
    contain = arr.some(function (k) {
        return k in primary;
    });

console.log(contain);

【讨论】:

    【解决方案2】:
    for (var i = 0; i< arr.length; i++){
        if (primary[arr[i]]){
            //exists
        }
    }
    

    【讨论】:

      【解决方案3】:

      您可以使用indexOf迭代对象的键并检查是否退出:

      for (property in primary){
             if (arr.indexOf(property) !== -1)
               console.log("Exists");
       };
      

      Object.keys:

      Object.keys(primary, function(key){
          if (arr.indexOf(key) !== -1)
              console.log("Exists"); 
      });
      

      【讨论】:

        【解决方案4】:

        使用Array.prototype.some的答案:

        var arr=["EMPRESA","CD_DIRECAO","DT_INI_DIRECAO"];
        var primary={EMPRESA:{type:"varchar"},CD_DIRECAO:{type:"varchar"},DT_INI_DIRECAO:{type:"date"},CD_DEPT:{type:"varchar"},DT_INI_DEPT:{type:"date"},ANO:{type:"number"},MES:{type:"number"},TP_CUSTO:{type:"varchar"}};
        
        var result = arr.some(function(element){
           return primary[element];
        });
        
        console.log(result);

        【讨论】:

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