将 ajaxform 数据发送到多个电子邮件地址答案

【问题标题】：Send ajaxform data to multiple email addresses将 ajaxform 数据发送到多个电子邮件地址
【发布时间】：2014-10-27 11:48:51
【问题描述】：

我希望将访问者填写的数据副本发送给我自己，并将另一份副本发送给访问者。请指教！

我的电子邮件是 myemail@mysite.com，而访问者的电子邮件是 $email

这段代码如下所示：

// Set the recipient email address.
    // FIXME: Update this to your desired email address.
    $recipient = "myemail@mysite.com, .$email";

点击提交按钮后我没有得到任何结果！

我将不胜感激！

   <?php
// My modifications to mailer script from:
// http://blog.teamtreehouse.com/create-ajax-contact-form
// Added input sanitizing to prevent injection

// Only process POST reqeusts.
if ($_SERVER["REQUEST_METHOD"] == "POST") {
    // Get the form fields and remove whitespace.
    $name = strip_tags(trim($_POST["name"]));
            $name = str_replace(array("\r","\n"),array(" "," "),$name);
    $email = filter_var(trim($_POST["email"]), FILTER_SANITIZE_EMAIL);
    $message = trim($_POST["message"]);

    // Check that data was sent to the mailer.
    if ( empty($name) OR empty($message) OR !filter_var($email, FILTER_VALIDATE_EMAIL)) {
        // Set a 400 (bad request) response code and exit.
        http_response_code(400);
        echo "Oops! There was a problem with your submission. Please complete the form and try again.";
        exit;
    }

    // Set the recipient email address.
    // FIXME: Update this to your desired email address.
    $recipient = "myemail@mysite.com, .$email";

    // Set the email subject.
    $subject = "New contact from $name";

    // Build the email content.
    $email_content = "Name: $name\n";
    $email_content .= "Email: $email\n\n";
    $email_content .= "Message:\n$message\n";

    // Build the email headers.
    $email_headers = "From: $name <$email>";

    // Send the email.
    if (mail($recipient, $subject, $email_content, $email_headers)) {
        // Set a 200 (okay) response code.
        http_response_code(200);
        echo "Thank You! Your message has been sent.";
    } else {
        // Set a 500 (internal server error) response code.
        http_response_code(500);
        echo "Oops! Something went wrong and we couldn't send your message.";
    }

} else {
    // Not a POST request, set a 403 (forbidden) response code.
    http_response_code(403);
    echo "There was a problem with your submission, please try again.";
}

【问题讨论】：

改用$recipient = "myemail@mysite.com, $email";（去掉点.）

标签： php ajax mailto ajaxform

【解决方案1】：

您必须将 myemail 和访问者电子邮件放在一个数组中，然后运行一个循环，相同的消息将发送给数组中的所有人。例如

$aEmails = array();
$aEmails[] = 'myemail@something.com';
$aEmails[] = 'visitoremail@something.com';

foreach(aEmails AS aEmail){
mail($aEmail, $subject, $email_content, $email_headers);
}

【讨论】：

谢谢。但我需要 'visitoremail@something.com' 作为变量。这意味着它应该是'$email'，因为每个访问者都会有一个唯一的电子邮件。我如何使用 $email 而不是 visitoremail@something.com 来实现这一点？
然后只需提供一个表格来填写并提交或登录来自任何其他网站（如 facebook、twitter 等）的访问者。这是您唯一可以获得他/她的电子邮件的地方。
非常感谢。我刚刚替换了“$aEmails[] = 'visitoremail@something.com';”与“$aEmails[] = $email';”它正在工作！

【解决方案2】：

如果你没有得到任何结果，那么你必须检查你的 html 表单的标签，它应该有 method="POST" 属性。

然后在这里去掉点

 $recipient = "myemail@mysite.com, .$email";

喜欢这个

$recipient = "myemail@mysite.com, $email";

【讨论】：