【发布时间】:2021-11-01 21:03:54
【问题描述】:
我有一个类来执行特定的逻辑如下:
public abstract class BaseSchema<T> : iMyInterface
{
public List<T> GetSchemaObjects<T>(string csvData) where T : iMyInterface
{
var records = new List<T>();
using (var streamReader = new StreamReader(csvData))
{
using (var csvReader = new CsvReader(streamReader, CultureInfo.InvariantCulture))
{
records = csvReader.GetRecords<T>().ToList();
}
}
return records;
}
}
现在我想用一个类作为参数来调用这个方法。我有该类的 Type 对象。调用时如何分配?
public List<T> GetTestSchema<T>(string versionNumber, string schemaName) where T : iMyInterface
{
Type[] allSchemaTypes = Assembly.GetExecutingAssembly().GetTypes()
.Where(t => t.IsClass && t.Namespace.StartsWith($"{schemaNamespace}")
&& !t.GetCustomAttributes(typeof(ObsoleteAttribute), true).Any())
.ToArray();
int indexNumber = GetIndexNumberOfRequiredVersion(versionNumber);
Type schemaType = allSchemaTypes
.Skip(indexNumber)
.Where(x => x.Name.Equals(schemaName) && interfaceType.IsAssignableFrom(x))
.FirstOrDefault();
var objj = (iMyInterface)schemaType.Assembly.CreateInstance(schemaType.ToString());
//Type objjType = Type.GetType(objj);
return objj.GetSchemaObjects<schemaType>(@"CSV Path"); // This line gives an error as Cannot implicitly convert type List<schemaType> to List<T> but generic should accept it. Isn't it?
}
【问题讨论】:
-
对于初学者,从那里获取
ToList()并将返回类型更改为IEnumerable<T>。如果你真的需要一个列表(通常你不需要,并且没有它你可以提高内存使用),你可以随时在方法调用站点添加 ToList()。
标签: c# generics interface constraints