iphone中调用者此时不拥有的对象的引用计数不正确递减

Question

我收到内存警告：标记行中的 challengeCell 的“调用者此时不拥有的对象的引用计数不正确递减”。

myIdentifier = @"ChallengTblVwCell";    
ChallengeTableViewCell *challengeCell = (ChallengeTableViewCell *)[tableView dequeueReusableCellWithIdentifier:myIdentifier];
if( challengeCell == nil )
{
    [[ NSBundle mainBundle ] loadNibNamed:@"ChallengeTableViewCell" owner:self options:nil ];
    challengeCell = challengeTblCell; 
}

else {
//some code
}           
        challengeInstance = [genericArray objectAtIndex:indexPath.row];
        NSString *challengeTitle = challengeInstance.elecompany;

        [challengeCell initWithTitle:challengeTitle subTitle:challengeSubtitle _votes:challengeVotes content:challengeContent _time:challengeTime _image:challengeImage noComments:challengeCommentsNo]; //Warning coming at this line
        return (UITableViewCell *)challengeCell;

编辑：

 -(id)initWithTitle:(NSString *)_title content:(NSString *)_content fromName:(NSString *)_fromName _time:(NSString *)_time_ _image:(NSString *)_image_ noComments:(NSInteger)commentsNo
 {
    //Labels are created through interface builder

[_lbltitle_ setText:_title];       
[_lbltime setText:_time_];
[lblcontent setText:_content];
[lblsubTitle setText:_fromName];
[lblnoOfComments setText:[NSString stringWithFormat:@"%d",commentsNo]];

// code for adjusting label height according to content.

return self;
}

我为单元格的管理创建了这个单独的类，以便于对其进行操作。

谁能帮我解决这个问题？

提前感谢。

Answer 1

如果您将 initWithTitle 的代码发布在这 2 行中会更好：

[challengeCell initWithTitle:challengeTitle subTitle:challengeSubtitle _votes:challengeVotes content:challengeContent _time:challengeTime _image:challengeImage noComments:challengeCommentsNo]; //Warning coming at this line
return (UITableViewCell *)challengeCell;

但我猜你已经有一个challengeCell 对象，已经分配和初始化。老实说，您的代码看起来真的很奇怪。通常，人们所做的将是[[UIChallengeCell alloc] initWithTitle...] 而不是来自实例本身。我认为这会造成您的问题。

你应该做的是自己设置属性。

challengeCell.challengeTitle = challengeTitle;
challengeCell.subTitle = challengeSubtitle;