按联邦财政年度重新排序月份答案

【问题标题】：Re-Ordering the Months By Federal Fiscal Year按联邦财政年度重新排序月份
【发布时间】：2015-04-13 17:55:51
【问题描述】：

运行以下查询时，我试图找到一种方法来按联邦财政年度显示返回的月份，而不是正常的顺序值。

（即我想按以下顺序显示月份 Oct、Nov、Dec、Jan、Feb、Mar、Apr、May、Jun、Jul、Aug、Sept 而不是 Jan 到 Dec。）谢谢

select wrkgrp,
    sum (case when extract(month from reportdate) = 1 then 1 else 0 end) as January,
    sum (case when extract(month from reportdate) = 2 then 1 else 0 end) as February,
    sum (case when extract(month from reportdate) = 3 then 1 else 0 end) as March,
    sum (case when extract(month from reportdate) = 4 then 1 else 0 end) as April,
    sum (case when extract(month from reportdate) = 5 then 1 else 0 end) as May,
    sum (case when extract(month from reportdate) = 6 then 1 else 0 end) as June,
    sum (case when extract(month from reportdate) = 7 then 1 else 0 end) as July,
    sum (case when extract(month from reportdate) = 8 then 1 else 0 end) as August,
    sum (case when extract(month from reportdate) = 9 then 1 else 0 end) as September,
    sum (case when extract(month from reportdate) = 10 then 1 else 0 end) as October,
    sum (case when extract(month from reportdate) = 11 then 1 else 0 end) as November,
    sum (case when extract(month from reportdate) = 12 then 1 else 0 end) as December,
from workorder
where reportdate between to_date ('2014-10-01 00:00:00', 'yyyy/mm/dd hh24:mi:ss')
and   to_date ('2015-09-30 00:00:00', 'yyyy/mm/dd hh24:mi:ss')
and   wrkgrp = 'PublicWorks'
group by 'wrkgrp;'

【问题讨论】：

标签： sql oracle11g

【解决方案1】：

这些字段将按照您在选择语句中列出的顺序（水平）显示在您的结果中。像这样首先列出 Oct 来构建您的语句：

select wrkgrp,
sum (case when extract(month from reportdate) = 10 then 1 else 0 end) as October,
sum (case when extract(month from reportdate) = 11 then 1 else 0 end) as November,
sum (case when extract(month from reportdate) = 12 then 1 else 0 end) as December,
sum (case when extract(month from reportdate) = 1 then 1 else 0 end) as January,
sum (case when extract(month from reportdate) = 2 then 1 else 0 end) as February,
sum (case when extract(month from reportdate) = 3 then 1 else 0 end) as March,
sum (case when extract(month from reportdate) = 4 then 1 else 0 end) as April,
sum (case when extract(month from reportdate) = 5 then 1 else 0 end) as May,
sum (case when extract(month from reportdate) = 6 then 1 else 0 end) as June,
sum (case when extract(month from reportdate) = 7 then 1 else 0 end) as July,
sum (case when extract(month from reportdate) = 8 then 1 else 0 end) as August,
sum (case when extract(month from reportdate) = 9 then 1 else 0 end) as September
from workorder
where reportdate between to_date ('2014-10-01 00:00:00', 'yyyy/mm/dd hh24:mi:ss') ad to_date ('2015-09-30 00:00:00', 'yyyy/mm/dd hh24:mi:ss') and
wrkgrp = 'PublicWorks'
group by 'wrkgrp;'

【讨论】：

【解决方案2】：

在 order by 子句中添加 case 语句以获得所需的排序。

ORDER BY 
CASE WHEN extract(month from reportdate) = 10 THEN 1 
CASE WHEN extract(month from reportdate) = 11 THEN 2 
ASC

【讨论】：