【问题标题】:Playground execution failed: <EXPR>:15:33: error: type 'Int' does not conform to protocol 'BooleanType'Playground 执行失败:<EXPR>:15:33:错误:类型“Int”不符合协议“BooleanType”
【发布时间】:2014-09-21 02:13:06
【问题描述】:

我正在使用 Swift 创建一个简单的Fizz Buzz Generator

我收到以下错误:

Playground execution failed: <EXPR>:15:33: error: type 'Int' does not conform to protocol 'BooleanType'
    } else if (number % 3 == 0) && (number % 5) {

这是我所拥有的:

for number in 1...100 {
    if (number % 3 == 0) {
        println("Fizz")
    } else if (number % 5 == 0) {
        println("Buzz")
    } else if (number % 3 == 0) && (number % 5) {
        println("Fizz Buzz")
    } else {
        println(number)
    }
}

【问题讨论】:

    标签: ios if-statement for-loop swift logical-operators


    【解决方案1】:

    你错过了一些你的逻辑。改变

    else if (number % 3 == 0) && (number % 5)
    

    else if (number % 3 == 0) && (number % 5 == 0)
    

    【讨论】:

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