【发布时间】:2018-12-07 07:01:14
【问题描述】:
我想将一些用户的所有消息分组到一个数组中。我怎样才能做到这一点?我有近 200 个用户,我想在单独的数组中显示每个用户的对话以及用户详细信息。
聊天表有 recipientId、senderId 消息、created_at 和 updated_at。
我已经尝试过了,但它会返回消息以及发件人详细信息:
models.chat.findAll({ include: [
{
model:models.User,
as: 'User'
}
],
order: [['senderId ']],
});
期望的输出:
[
{
"id": 5,
"username": "username",
"email": "username@gmail.com.com",
"password": "o15G8DdMqRE0Ksm",
"created_at": "2018-12-07T05:46:05.590Z",
"updated_at": "2018-12-07T05:46:05.590Z"
"messages":
[
{
"id": 5,
"message": "hi",
"senderId ": 1,
"recipientId": 5,
"created_at": "2018-12-07T05:53:48.229Z",
"updated_at": "2018-12-07T05:53:48.229Z",
},
{
"id": 7,
"message": "how are you",
"senderId ": 5,
"recipientId": 1,
"created_at": "2018-12-07T05:53:48.229Z",
"updated_at": "2018-12-07T05:53:48.229Z"
},
{...},
{...}
]
},
]
聊天模式:
chat.associate = (models) => {
chat.belongsTo(models.User, {
foreignKey: 'senderId',
onDelete: 'CASCADE'
});
chat.belongsTo(models.User, {
foreignKey: 'recipientId',
onDelete: 'CASCADE'
});
};
用户模型:
const User = sequelize.define('User', {
username: {
type: DataTypes.STRING
},
email: {
type: DataTypes.STRING,
allowNull: false,
unique: true
},
password: {
type: DataTypes.STRING,
allowNull: false
}
}, {
underscored: true,
freezeTableName: true,
tableName: 'users',
hooks: {
beforeCreate: beforeCreate,
beforeBulkUpdate: beforeBulkUpdate
}
});
User.associate = (models) => {
User.hasMany(models.Message, {
foreignKey: 'fromUserId',
as: 'messages'
});
User.hasMany(models.Message, {
foreignKey: 'toUserId',
as: 'messagess'
});
};
【问题讨论】:
标签: postgresql group-by include sequelize.js