如何以字符串形式执行 Django Query答案

【问题标题】：How to execute Django Query as string如何以字符串形式执行 Django Query
【发布时间】：2018-09-19 16:48:25
【问题描述】：

我想在 Django ORM 中进行这样的查询：

query_string = "optionA=True,optionB=True,optionC=True"
data = ModelObject.objects.filter(query_string)

此代码给出以下错误：

Traceback (most recent call last):
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/core/handlers/exception.py", line 41, in inner
response = get_response(request)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 187, in _get_response
response = self.process_exception_by_middleware(e, request)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 185, in _get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/views/decorators/csrf.py", line 58, in wrapped_view
return view_func(*args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/views/generic/base.py", line 68, in view
return self.dispatch(request, *args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/rest_framework/views.py", line 483, in dispatch
response = self.handle_exception(exc)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/rest_framework/views.py", line 443, in handle_exception
self.raise_uncaught_exception(exc)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/rest_framework/views.py", line 480, in dispatch
response = handler(request, *args, **kwargs)
File "/root/hellomeets/hellomeets/frontend/views.py", line 74, in post
filtered_emails = HelloMeetsMailList.objects.filter(final_query)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/manager.py", line 85, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/query.py", line 784, in filter
return self._filter_or_exclude(False, *args, **kwargs)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/query.py", line 802, in _filter_or_exclude
clone.query.add_q(Q(*args, **kwargs))
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1250, in add_q
clause, _ = self._add_q(q_object, self.used_aliases)
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1276, in _add_q
allow_joins=allow_joins, split_subq=split_subq,
File "/root/hellomeets/.env/hellomeets/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1151, in build_filter
arg, value = filter_expr
ValueError: too many values to unpack

我也试过 eval() 但它没有用。有什么办法让我不需要编写原始的 sql 查询

【问题讨论】：

你是怎么把这个放在first的地方的？处理查询的方法看起来有问题，甚至可能容易出错、黑客攻击等。
re sugiero realizar algo como esto: stackoverflow.com/questions/7212847/…

标签： django django-models

【解决方案1】：

from django.db.models import Q

query_string=Q(optionA=True) & Q(optionB=True) & Q(optionC=True)
data = ModelObject.objects.filter(query_string)

【讨论】：

【解决方案2】：

如果您真的需要使用该字符串（这似乎是一种非常笨拙的方式来查询 Django 模型），您可以将其拆分并转换为 dict：

s = "optionA=True,optionB=True,optionC=True"
kwargs = {}
for e in s.split(','):
    k, v = e.split('=')
    kwargs[k] = bool(v)

然后在 filter() 方法中解压该字典

data = ModelObject.objects.filter(**kwargs)

但这并不是真的推荐！！！

【讨论】：

谢谢，这正是我要找的。尽管这些查询仅在内部服务内部传递。