【发布时间】:2017-07-22 21:59:45
【问题描述】:
我有一个格式为 RDD[((Long, Long), (Long, Long))] 的 RDD,我需要转换或转换为 RDD[((Long, Long), (Long, Long, Long, Long ))] 其中第二个 RDD 元组基于第一个 RDD 中的函数。
我正在尝试实现这个基于地图的功能,但是我认为这里做错了。请帮我解决问题。
这里是完整的代码:
package com.ranker.correlation.listitem
import org.apache.spark.SparkConf
import org.apache.spark.SparkContext
import org.apache.spark.SparkContext._
import org.apache.spark.rdd._
import scala.collection.Map
class ListItemCorrelation(sc: SparkContext) extends Serializable {
def up_down(dirX: Long, dirY: Long): (Long, Long, Long, Long) = {
if (dirX.equals(1)) {
if (dirY.equals(1)) {
return (1, 0, 0, 0)
} else {
return (0, 1, 0, 0)
}
} else {
if (dirY.equals(1)) {
return (0, 0, 1, 0)
} else {
return (0, 0, 0, 1)
}
}
}
def run(votes: String): RDD[((Long, Long), (Long, Long, Long, Long))] = {
val userVotes = sc.textFile(votes)
val userVotesPairs = userVotes.map { t =>
val p = t.split(",")
(p(0).toLong, (p(1).toLong, p(2).toLong))
}
val jn = userVotesPairs.join(userVotesPairs).values.filter(t => t._1._1.<(t._2._1))
val first = jn.map(t => ((t._1._1, t._2._1), (t._1._2, t._2._2)))
var second = first.map(t => ((t._1._1, t._2._1), up_down(t._1._2, t._2._2)))
//More functionality
return result
}
}
object ListItemCorrelation extends Serializable {
def main(args: Array[String]) {
val votes = args(0)
val conf = new SparkConf().setAppName("SparkJoins").setMaster("local")
val context = new SparkContext(conf)
val job = new ListItemCorrelation(context)
val results = job.run(votes)
val output = args(1)
results.saveAsTextFile(output)
context.stop()
}
}
当我尝试运行此脚本时,出现以下错误:
线程“主”org.apache.spark.SparkException 中的异常:任务不是 可序列化在 org.apache.spark.util.ClosureCleaner$.ensureSerializable(ClosureCleaner.scala:298) 在 org.apache.spark.util.ClosureCleaner$.org$apache$spark$util$ClosureCleaner$$clean(ClosureCleaner.scala:288) 在 org.apache.spark.util.ClosureCleaner$.clean(ClosureCleaner.scala:108) 在 org.apache.spark.SparkContext.clean(SparkContext.scala:2094) 在 org.apache.spark.rdd.RDD$$anonfun$map$1.apply(RDD.scala:370) 在 org.apache.spark.rdd.RDD$$anonfun$map$1.apply(RDD.scala:369) 在 org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:151) 在 org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:112) 在 org.apache.spark.rdd.RDD.withScope(RDD.scala:362) 在 org.apache.spark.rdd.RDD.map(RDD.scala:369) 在 com.ranker.correlation.listitem.ListItemCorrelation.run(ListItemCorrelation.scala:34) 在 com.ranker.correlation.listitem.ListItemCorrelation$.main(ListItemCorrelation.scala:47) 在 com.ranker.correlation.listitem.ListItemCorrelation.main(ListItemCorrelation.scala) 引起:java.io.NotSerializableException: org.apache.spark.SparkContext 序列化栈: - 对象不可序列化(类:org.apache.spark.SparkContext,值:org.apache.spark.SparkContext@4248e66b) - 字段(类:com.ranker.correlation.listitem.ListItemCorrelation,名称:sc,类型:类 org.apache.spark.SparkContext) - 对象(com.ranker.correlation.listitem.ListItemCorrelation 类,com.ranker.correlation.listitem.ListItemCorrelation@270b6b5e) - 字段(类:com.ranker.correlation.listitem.ListItemCorrelation$$anonfun$4,名称: $外部,类型:类 com.ranker.correlation.listitem.ListItemCorrelation) - 对象(com.ranker.correlation.listitem.ListItemCorrelation$$anonfun$4 类, ) 在 org.apache.spark.serializer.SerializationDebugger$.improveException(SerializationDebugger.scala:40) 在 org.apache.spark.serializer.JavaSerializationStream.writeObject(JavaSerializer.scala:46) 在 org.apache.spark.serializer.JavaSerializerInstance.serialize(JavaSerializer.scala:100) 在 org.apache.spark.util.ClosureCleaner$.ensureSerializable(ClosureCleaner.scala:295) ... 12 更多
执行以下行时发生此错误:
var second = first.map(t => ((t._1._1, t._2._1), up_down(t._1._2, t._2._2)))
我对 scala 很陌生,请帮助我找到正确的方法。
【问题讨论】:
-
将
SparkContext下推作为run的参数?用当前的实现会一直拖下去,由于不是序列化,导致失败。 -
@geek:你找到解决方案了吗?
标签: scala apache-spark serialization