ServiceStack：使用自托管应用程序重写 URL

Question

我有一个自托管应用程序，它的根目录有一个index.html 文件。当我运行应用程序并转到localhost:8090（应用程序托管在此端口上）时，URL 看起来像：http://localhost:8090/index.html。无论如何我可以在 index.html 页面上将 URL 设为：http://localhost:8090？

注意

我正在使用 ServiceStack V3

Answer 1

ServiceStack v4

在 ServiceStack v4 中，我使用原始 http 处理程序来拦截根。在您的 AppHost Configure 方法中：

public override void Configure(Container container)
{
    var handleRoot = new CustomActionHandler((httpReq, httpRes) => {
        httpRes.ContentType = "text/html";
        httpRes.WriteFile("index.html");
        httpRes.End();
    });

    RawHttpHandlers.Add(httpReq => (httpReq.RawUrl == "/") ? handleRoot : null);
}

ServiceStack v3

在 ServiceStack v3 中，您可以做类似的事情，但您必须自己包含 CustomActionHandler 类。所以在你的配置方法中：

public override void Configure(Container container)
{
    var handleRoot = new CustomActionHandler((httpReq, httpRes) => {
        httpRes.ContentType = "text/html";
        httpRes.WriteFile("index.html");
        httpRes.End();
    });

    SetConfig(new EndpointHostConfig {
        RawHttpHandlers = { httpReq => (httpReq.RawUrl == "/") ? handleRoot : null  },
    });
}

CustomActionHandler提供by Mythz here：

public class CustomActionHandler : IServiceStackHttpHandler, IHttpHandler 
{
    public Action<IHttpRequest, IHttpResponse> Action { get; set; }

    public CustomActionHandler(Action<IHttpRequest, IHttpResponse> action)
    {
        if (action == null)
            throw new Exception("Action was not supplied to ActionHandler");

        Action = action;
    }

    public void ProcessRequest(IHttpRequest httpReq, IHttpResponse httpRes, string operationName)
    {            
        Action(httpReq, httpRes);
    }

    public void ProcessRequest(HttpContext context)
    {
        ProcessRequest(context.Request.ToRequest(GetType().Name), 
            context.Response.ToResponse(),
            GetType().Name);
    }

    public bool IsReusable
    {
        get { return false; }
    }
}

希望对您有所帮助。